Magnitude of an electric force problem with vectors

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Homework Help Overview

The discussion revolves around calculating the magnitude of the electric force on a charge Q due to two equal positive charges. The context involves vector components of electric forces and their summation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss breaking down the electric forces into their x and y components. There is uncertainty about the correct trigonometric functions to use and the overall approach to summing these components.

Discussion Status

Some participants are clarifying the mathematical expressions used for the components of the forces and are exploring the implications of balancing forces. There is an ongoing exchange about the correctness of the expressions and the next steps in the calculation.

Contextual Notes

Participants are working with the assumption that the charges are positioned in a specific configuration, which affects the direction of the forces. There is mention of a diagram that is not visible in the thread, which may be crucial for understanding the problem setup.

AladdinSane
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Homework Statement


Two equal positive charges, both q = 2.0 x 10^ -6 C, interact with a third charge Q = 4.0 x 10^ -6 C, as shown above. What is the magnitude of the electric force on Q?[/B][/B]



Homework Equations


Electric force = Kc (q1/r^2)


The Attempt at a Solution


Basically, I believe that my problem is in solving the vectors.
I attempted to break down the charges(it is hard to show this work on here but...) I broke it down into...
E(y) = E(1) x sin Θ(1) + E(2) x sin Θ(2)
E(x) = E(1) x cox Θ(1) - E(2) sin Θ(2)
I'm not sure if that makes sense, but it was all I could think of...Any help would be greatly appreciated. Thanks a lot!
 

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AladdinSane said:
E(x) = E(1) x cox Θ(1) - E(2) sin Θ(2)
I'm sure you meant "cos", not "sin" there right?

While waiting for the image, it sounds like your reasoning is correct. You are summing the x and y components of the separate forces on the thrid charge. Next you need to determine the net force.

Hey, how did you type those thetas in there?
 
Last edited:
thanks chi,
so i believe my second set should actually look like...
E(x) = E(1) x cosx Θ(1) - E(2) cos Θ(2)
then once i plug in my values and simplify, i should get my x component any my y component, right? then i just use the pythagorean theorem to solve?

oh, and for the thetas i just happened to come across one on a wensite and i copied and pasted. .
 
Θ

wow, must be some ASCII trick.Anyway, now that I see the drawing, please notice that the two vertical components are balancing out while the two horizontal components are working together. Simpler now, isn't it?
 

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