Magnitude of Electric Field problem

[jlone]

Homework Statement

If q+ve=2.01 nC, q-ve=-2.01 nC, d1=3.28 cm, and d2=6.56 cm, what is the magnitude of the electric field at the position C?

Homework Equations

E=E1 + E2 E1=kq/r E2=kq/r

The Attempt at a Solution

I still can't get this, any help please

this is what I've done so far -- if u notice what I am doing wrong pleaseeeeee point it out

first, i got E from Q1 using kq/r (squared) = 1.68E7
then i got E from Q2 using kq/r (squared) -- found r using a squared+b squared= c
squared

then i started on getting the x and y components of each.
we know E from Q1 is only x component, and so x = 1.68E7 while y=0

E2 is at an angle
(i think i might be doing this part wrong) = sin angle = d2/r (found above) , angle is 63
degrees

x component of E2= E2cos63
y component of E2= E2sin63

now i add the two x together (E1)+ (-e2) and I have the neg Y

then i use phyth. theorem to get r in N/C

what am i doing wrong ?

(i then went back and unsquared all my r values for kq/rSquared into kq/r and it still don't work)

 

[<---]

Mabey It's just me, but I don't get the problem.
What is "q+ve"? (I know it's a charge but what kind, I don't understand the +/- ve)
Also, what are d1 and d2? Distances from what?
Does the point c have a special location like any axis, or is it just any point c?

 

[Feldoh]

q+ve=2.01 nC, q-ve=-2.01 nC - Sorta looks like a dipole, but I don't really understand the problem either...