If q+ve=2.01 nC, q-ve=-2.01 nC, d1=3.28 cm, and d2=6.56 cm, what is the magnitude of the electric field at the position C?
E=E1 + E2 E1=kq/r E2=kq/r
The Attempt at a Solution
I still can't get this, any help please
this is what I've done so far -- if u notice what I am doing wrong pleaseeeeee point it out
first, i got E from Q1 using kq/r (squared) = 1.68E7
then i got E from Q2 using kq/r (squared) -- found r using a squared+b squared= c
then i started on getting the x and y components of each.
we know E from Q1 is only x component, and so x = 1.68E7 while y=0
E2 is at an angle
(i think i might be doing this part wrong) = sin angle = d2/r (found above) , angle is 63
x component of E2= E2cos63
y component of E2= E2sin63
now i add the two x together (E1)+ (-e2) and I have the neg Y
then i use phyth. theorm to get r in N/C
what am i doing wrong ?
(i then went back and unsquared all my r values for kq/rSquared into kq/r and it still don't work)