Magnitude of the electric force a hydrogen nucleus exerts on electron?

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SUMMARY

The magnitude of the electric force exerted by a hydrogen nucleus on its orbiting electron in the Bohr model is calculated using Coulomb's law, represented by the formula Fe = kQq/r². In this case, both Q and q are equal to 1.6 x 10^-19 C, with k being 9 x 10^9 N m²/C² and the radius typically taken as 5.3 x 10^-11 m. The calculated force should be expressed to one significant figure, yielding an order of magnitude of 10^-7 N. Discrepancies in results, such as obtaining 1.7 x 10^-7 N, are attributed to the use of incorrect radius values or significant figure conventions.

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  • Knowledge of significant figures in scientific calculations
  • Familiarity with SI units and their application in physics
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Students studying physics, particularly those focusing on electromagnetism and atomic theory, as well as educators seeking to clarify concepts related to electric forces and the Bohr model.

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Homework Statement



What is the magnitude of the electric force a hydrogen nucleus exerts on its only orbiting electron in the Bohr model?

The Attempt at a Solution



Fe = kQq/r^2

Since there is one proton and one electron. Q and q are equal to each other: 1.6 x 10^-19.
k = 9 x 10^9
and radius = 40 x 10^-19.

All the values are given in the question.

The answer is 10^-7 but I got 1.7 x 10^-7.

Why did they completely disregard the 1.7 ?
 
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It's called an "order of magnitude" calculation.
Though it may be a typo - depends: who is "they"?

Note: don't forget the units.
 
Thank you I shall look into that! Sorry they is the people who wrote the solution manual and I will remember to include units next time!
 
No worries - also remember, when you refer to the work of others, to include their names and the title of the work in question. Otherwise the reference is meaningless. ;)

Note: if you use k=9x10^9 SI units, then your answer should be to 1 sig fig too.
 
Isn't the radius supposed to be (5.3 x 10-11)?? How did you get (40 x 10-19)??

I solved the problem the same way you did so (except that i switched the radius) and found that the answer came to be -0.82 x 10-7 C.
 
Bohr radius (order e-11) would be a good choice, yes... you could akso have used e-10 (angstrom = order of magnitude size of an atom) OPs order e-19 meters would be inside the nucleus.

Note. Dont forget units, and justify/critique guessed numbers using a physical reference. Youd probably get away with it is a secondary course but college usually penalises you if you use the correct value without indicating why. IRL if you do this you don't get published/paid.
 

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