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## Homework Statement

a proton is projected perpendicularly into a magnetic field that has a magnitude of .5 T. the field is then adjusted so that an electron will follow a circular path of the same radius when it is projected perpendicularly into the field with the same velocity that the proton had. What is the magnitude of the field used for the electron?

## Homework Equations

r=mv/qB

## The Attempt at a Solution

i basically used the above equation to solve for r but left v=1 since it is the same in both then used B=mv/qr and plugged in r and realized i just did the same thing so can someone please help explain what i have to do in detail since i am lost. Thanks for any help