Making Piecewise Function Continuous w/ First & Second Derivatives

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To make a piecewise function continuous at x=0 with both first and second derivatives, the user successfully equated the limits of the function and found a value for variable a. The first derivatives from both sides are equal, confirming first derivative continuity. However, the second derivatives differ, with one approaching infinity and the other zero, raising questions about the feasibility of achieving second derivative continuity. The discussion emphasizes the need for clarity regarding the relationship between variables a and b and the specific piecewise function involved. Understanding these aspects is crucial for determining the overall continuity of the piecewise function.
Dollydaggerxo
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I have to make a piecewise function continuous with first and second derivatives at x=0 by finding a value for a and b.

I have made the function continuous by equating the RHS and LHS limits and then solving for the variable a.

The limit of the first derivatives of the LHS and RHS are the same, both 0, so that makes the first derivative continuous...

However, the limits of the second derivates for the RHS and LHS are different. One is infinty when the other is 0.

My question is what does this mean exactly? Is the question not possible if my second derivatives are not continuous?
 
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First, please tell us what the problem really is! You say "by finding a value of a and b" but tell us nothing about how "a" and "b" are related to the function. Are you given a formula for the function involving a and b? If so, that formula is important information.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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