Manipulation of an analytic function

  • Thread starter thayin
  • Start date
  • #1
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Can anyone point out a way to get f(z) = z + e^h(z) into the form f(z) = (1-e^(z*h(z)))/z

I have used all of the algebra tricks I know and it seems to be going nowhere.
 

Answers and Replies

  • #2
1,796
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Did you try plugging in a number say z=1 to make sure they're equivalent?
 
  • #3
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I know they are equivalent. I am trying to understand a result not come up with a new one.
 
  • #4
Office_Shredder
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Is h(z) a specific function that you haven't mentioned? Because this is not true in general. For example if h(z)=z we get
[tex]z+e^z=\frac{1-e^{z^2}}{z}[/tex]
Plugging in z=1 we get
[tex] 1+e=1-e[/tex]
which seems unlikely
 

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