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Manipulation of an analytic function

  1. Apr 27, 2012 #1
    Can anyone point out a way to get f(z) = z + e^h(z) into the form f(z) = (1-e^(z*h(z)))/z

    I have used all of the algebra tricks I know and it seems to be going nowhere.
     
  2. jcsd
  3. Apr 27, 2012 #2
    Did you try plugging in a number say z=1 to make sure they're equivalent?
     
  4. Apr 28, 2012 #3
    I know they are equivalent. I am trying to understand a result not come up with a new one.
     
  5. Apr 28, 2012 #4

    Office_Shredder

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    Is h(z) a specific function that you haven't mentioned? Because this is not true in general. For example if h(z)=z we get
    [tex]z+e^z=\frac{1-e^{z^2}}{z}[/tex]
    Plugging in z=1 we get
    [tex] 1+e=1-e[/tex]
    which seems unlikely
     
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