- #1

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I have used all of the algebra tricks I know and it seems to be going nowhere.

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- Thread starter thayin
- Start date

- #1

- 4

- 0

I have used all of the algebra tricks I know and it seems to be going nowhere.

- #2

- 1,796

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Did you try plugging in a number say z=1 to make sure they're equivalent?

- #3

- 4

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I know they are equivalent. I am trying to understand a result not come up with a new one.

- #4

Office_Shredder

Staff Emeritus

Science Advisor

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[tex]z+e^z=\frac{1-e^{z^2}}{z}[/tex]

Plugging in z=1 we get

[tex] 1+e=1-e[/tex]

which seems unlikely

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