Marching Band doppler effect with Beat Frequency.

AI Thread Summary
Emma's movement toward Don causes a Doppler effect, resulting in a higher pitch frequency that Don tunes to. When Emma stops, Don detects a beat frequency of 5 Hz, indicating a drop in frequency back to the original note. The relationship between Emma's speed and the frequency she emits can be expressed using the formula fobs = f0[(v)/(v-vEmma)]. This equation shows how her speed affects the observed frequency. Understanding this relationship is crucial for solving the problem effectively.
Ethan_Tab
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Homework Statement


Emma and Don are playing in a band. While emma is marching toward Don, Don tunes his instrument to match the note that emma is playing. When emma stops, don immediately notices a beat frequency of 5 Hz. If the speed of the sound is 330m/s what is the relationship between Emmas speed and the frequency she is emmiting?

Homework Equations


fobs=f0[(v)/(v+-vsource)]
Bear Frequency= |f2-f1|
v=ƒλ

The Attempt at a Solution


at the speed which emma is moving, her note due to the doppler effect is shifted to a higher pitch which is what don tunes his instrument too. when she stops, the frequency of emmas note drops by 5Hz, to the actual note which was truly being played. Thats all i understand... what's the best way to get started?
 
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Just to add to what I just said, we can represent that first part through

fobs=f0+5
therfore
f0+5=f0[(v)/(v-vEmma)]
 
Ethan_Tab said:
what is the relationship between Emmas speed and the frequency she is emmiting?
Ethan_Tab said:
f0+5=f0[(v)/(v-vEmma)]

Isn't that a relationship between Emma's speed and the frequency she's playing? So what's the problem?
 

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