Markov Chain Conditional Expectation

tunaaa
Messages
12
Reaction score
0
Hello, in relation to Markov chains, could you please clarify the following equations:

j5b987.jpg


In particular, could you please expand on why the first line is equal. Surely from
gif.gif
, along with the first equation, this implies that:

2nk01nr.gif


I just don't see why they are all equal. Please could you provide some intuition on this. Thanks
 

Attachments

  • j5b987.jpg
    j5b987.jpg
    2.3 KB · Views: 499
Physics news on Phys.org
tunaaa said:
Hello, in relation to Markov chains, could you please clarify the following equations:

j5b987.jpg


In particular, could you please expand on why the first line is equal. Surely from
gif.gif
, along with the first equation, this implies that:

2nk01nr.gif


I just don't see why they are all equal. Please could you provide some intuition on this. Thanks

The Markov property is where the probability of the present state n is conditional only on the probability of the immediately preceding state n-1. There's no dependence on prior states n-i for integer i; 1<i\leq n.
 

Attachments

  • j5b987.jpg
    j5b987.jpg
    2.3 KB · Views: 439
OK, sure - but how is that fact relevant to understanding the above equation? Thanks.
 
tunaaa said:
OK, sure - but how is that fact relevant to understanding the above equation? Thanks.

Given the Markov property, if P(X_{n}=j|(X_{0}=j), then under what two conditions could this be true?
 
Last edited:
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Back
Top