Mass difference due to electrical potential energy

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SUMMARY

The forum discussion centers on the relationship between electrical potential energy and the mass difference between protons and neutrons. Participants explore the quark composition of protons and neutrons, noting that protons consist of two up quarks and one down quark, while neutrons are made of two down quarks and one up quark. The potential energy of a uniformly charged sphere is calculated using the formula U = k(3/5)((Q^2)/R), leading to a discussion about whether this energy can explain the mass difference, which ultimately is determined to be insufficient due to the incorrect sign of the calculated energy.

PREREQUISITES
  • Understanding of particle physics concepts, specifically quark composition.
  • Familiarity with the formula for electric potential energy of a charged sphere: U = k(3/5)((Q^2)/R).
  • Knowledge of Einstein's mass-energy equivalence principle, E=mc².
  • Basic calculus for evaluating integrals related to electric fields.
NEXT STEPS
  • Research the implications of quark mass differences on particle stability and interactions.
  • Learn about the strong force and its contribution to the mass of protons and neutrons.
  • Study the derivation and applications of the electric potential energy formula for various charge distributions.
  • Explore advanced topics in quantum mechanics related to particle physics and mass-energy equivalence.
USEFUL FOR

Physics students, particle physicists, and anyone interested in understanding the fundamental principles of mass-energy relationships and the structure of matter.

  • #31
Adams2020 said:
Do I have to use both electric fields? That is, I have to use both the electric field inside the sphere and outside the sphere ?

Yeah, you would need to split the integral into$$U = 2\pi \varepsilon_0 \int_0^\infty E^2 r^2 dr = 2\pi \varepsilon_0 \int_0^R \frac{k^2 Q^2 r^4}{R^6} dr + 2\pi \varepsilon_0 \int_R^\infty \frac{k^2 Q^2}{r^2} dr$$
 
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  • #32
etotheipi said:
Yeah, you would need to split the integral into$$U = 2\pi \varepsilon_0 \int_0^\infty E^2 r^2 dr = 2\pi \varepsilon_0 \int_0^R \frac{k^2 Q^2 r^4}{R^6} dr + 2\pi \varepsilon_0 \int_R^\infty \frac{k^2 Q^2}{r^2} dr$$
The results of this way should be the same as the previous way, right?
 
  • #33
I've not seen andy previous way in this thread, only guesses about factors, which haven't been before either ;-)).
 
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  • #34
Adams2020 said:
The results of this way should be the same as the previous way, right?
Yes, the result is exactly the same. I got the previous formula.
Thank you and those who guided me in this exercise.
 
  • #35
etotheipi said:
The sign is incorrect, so this certainly cannot account for the mass difference. The protons are actually less heavy than the neutrons, not the other way around. Did I miss something?
You did not. But it's not your exercise !
 
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  • #36
BvU said:
You did not. But it's not your exercise !

Well no, but I thought you had endorsed the statement "Can the mass difference between protons and neutrons be due to the electrical potential energy of the protons?" as being plausible by consideration of ##E=mc^2##. I had pointed out in #16 that there was no need to perform the calculation, since we already know the electric potential energy would increase, rather than decrease, the mass! :smile:
 
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  • #37
You and I already knew. OP was supposed to discover ##-##1.3 MeV/c2 mass difference can not be explained with a ##+##1 MeV/c2 from electrostatic energy
 
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  • #38
Whoops... now I realized you had said "can you answer... affirmatively", instead of saying 'affirmative' to the quote. Please forgive my naivety, I'm not good at interpreting subtext :wink:
 
  • #39
I came back.:smile: I still have a knot in understanding this exercise. :frown:
Now the values are almost equal. That is, the potential difference is equal to the mass difference. What exactly does this mean? That is, how do you analyze this?
 
  • #40
Adams2020 said:
I came back.:smile: I still have a knot in understanding this exercise. :frown:
No problem
Now the values are almost equal.
What about the sign ?
That is, the potential difference is equal to the mass difference.
What about the sign ?
What exactly does this mean? That is, how do you analyze this?
Re-read the thread at leisure :smile:
The notion that mass and energy are "interchangeable" is not easy to grasp (It took an Einstein to find out :wink: )
 
  • #41
BvU said:
What about the sign ?
Yes. I did not pay attention to it. 😕 I thought the exercise was solved!☺
BvU said:
The notion that mass and energy are "interchangeable" is not easy to grasp (It took an Einstein to find out :wink: )
👍🙃🙂
 

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