Mass difference due to electrical potential energy

Click For Summary

Homework Help Overview

The discussion revolves around the relationship between electrical potential energy and mass difference, particularly focusing on protons and neutrons. Participants explore the implications of quark composition and the energy associated with charged spheres in the context of particle physics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants question the connection between potential energy and mass difference, while others discuss the quark structure of protons and neutrons. There are attempts to calculate the potential energy of a uniformly charged sphere and its implications for mass difference.

Discussion Status

Participants are actively engaging with the problem, raising questions about calculations and interpretations of results. Some guidance has been provided regarding potential energy calculations, but there is no explicit consensus on the relationship between the calculated energy and the mass difference.

Contextual Notes

There are references to homework rules that require effort from participants, and discussions about the prerequisites for understanding the problem suggest varying levels of familiarity with the subject matter.

  • #31
Adams2020 said:
Do I have to use both electric fields? That is, I have to use both the electric field inside the sphere and outside the sphere ?

Yeah, you would need to split the integral into$$U = 2\pi \varepsilon_0 \int_0^\infty E^2 r^2 dr = 2\pi \varepsilon_0 \int_0^R \frac{k^2 Q^2 r^4}{R^6} dr + 2\pi \varepsilon_0 \int_R^\infty \frac{k^2 Q^2}{r^2} dr$$
 
  • Like
Likes   Reactions: Adams2020 and vanhees71
Physics news on Phys.org
  • #32
etotheipi said:
Yeah, you would need to split the integral into$$U = 2\pi \varepsilon_0 \int_0^\infty E^2 r^2 dr = 2\pi \varepsilon_0 \int_0^R \frac{k^2 Q^2 r^4}{R^6} dr + 2\pi \varepsilon_0 \int_R^\infty \frac{k^2 Q^2}{r^2} dr$$
The results of this way should be the same as the previous way, right?
 
  • #33
I've not seen andy previous way in this thread, only guesses about factors, which haven't been before either ;-)).
 
  • Like
Likes   Reactions: etotheipi
  • #34
Adams2020 said:
The results of this way should be the same as the previous way, right?
Yes, the result is exactly the same. I got the previous formula.
Thank you and those who guided me in this exercise.
 
  • #35
etotheipi said:
The sign is incorrect, so this certainly cannot account for the mass difference. The protons are actually less heavy than the neutrons, not the other way around. Did I miss something?
You did not. But it's not your exercise !
 
  • Like
Likes   Reactions: etotheipi
  • #36
BvU said:
You did not. But it's not your exercise !

Well no, but I thought you had endorsed the statement "Can the mass difference between protons and neutrons be due to the electrical potential energy of the protons?" as being plausible by consideration of ##E=mc^2##. I had pointed out in #16 that there was no need to perform the calculation, since we already know the electric potential energy would increase, rather than decrease, the mass! :smile:
 
  • Like
Likes   Reactions: vanhees71
  • #37
You and I already knew. OP was supposed to discover ##-##1.3 MeV/c2 mass difference can not be explained with a ##+##1 MeV/c2 from electrostatic energy
 
  • Like
Likes   Reactions: etotheipi
  • #38
Whoops... now I realized you had said "can you answer... affirmatively", instead of saying 'affirmative' to the quote. Please forgive my naivety, I'm not good at interpreting subtext :wink:
 
  • #39
I came back.:smile: I still have a knot in understanding this exercise. :frown:
Now the values are almost equal. That is, the potential difference is equal to the mass difference. What exactly does this mean? That is, how do you analyze this?
 
  • #40
Adams2020 said:
I came back.:smile: I still have a knot in understanding this exercise. :frown:
No problem
Now the values are almost equal.
What about the sign ?
That is, the potential difference is equal to the mass difference.
What about the sign ?
What exactly does this mean? That is, how do you analyze this?
Re-read the thread at leisure :smile:
The notion that mass and energy are "interchangeable" is not easy to grasp (It took an Einstein to find out :wink: )
 
  • #41
BvU said:
What about the sign ?
Yes. I did not pay attention to it. 😕 I thought the exercise was solved!☺
BvU said:
The notion that mass and energy are "interchangeable" is not easy to grasp (It took an Einstein to find out :wink: )
👍🙃🙂
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
248
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K