Phymath
- 183
- 0
well while I am assuming I am just an idiot and this is wrong check it out...
\lambda = \frac{h}{p}
c = f \lambda
p = \frac{hf}{c}
\frac{c}{f} = \lambda = \frac{h}{p}
\frac{c}{f} = \frac{h}{mv} v = c for a photon..
m = \frac{fh}{c^2}->m = \frac{E}{c^2}
while this is most likely hugely flawed it brings me to a question...if momentum of a photon is the above 3rd orginal equation, the momentum would increase as the frequency increases, and sense any EM radiation v = c the "mass" of the photon would have to change in a classical view p = mv so...whos to say that photons of all frequencies must have the same mass? let me know what everyones think'n!
\lambda = \frac{h}{p}
c = f \lambda
p = \frac{hf}{c}
\frac{c}{f} = \lambda = \frac{h}{p}
\frac{c}{f} = \frac{h}{mv} v = c for a photon..
m = \frac{fh}{c^2}->m = \frac{E}{c^2}
while this is most likely hugely flawed it brings me to a question...if momentum of a photon is the above 3rd orginal equation, the momentum would increase as the frequency increases, and sense any EM radiation v = c the "mass" of the photon would have to change in a classical view p = mv so...whos to say that photons of all frequencies must have the same mass? let me know what everyones think'n!
Last edited: