Mass of escaped air from a cylinder

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SUMMARY

The discussion revolves around calculating the mass of air escaping from a compressed air cylinder when moved from a storage room at 7 °C to a workshop at 27 °C. The cylinder initially contains 19 kg of air at a pressure of 9.5 times atmospheric pressure. Upon reaching the workshop, the safety valve activates when the pressure exceeds 10 times atmospheric pressure, resulting in an escape of 0.33 kg of air. The calculations utilize the ideal gas law and density of air at standard conditions to derive the volume and mass before and after the escape.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Knowledge of air density at standard temperature and pressure (1.293 kg/m³)
  • Familiarity with pressure conversions (atmospheric pressure to gauge pressure)
  • Basic thermodynamics concepts related to temperature and pressure changes
NEXT STEPS
  • Study the Ideal Gas Law in detail, focusing on applications in real-world scenarios.
  • Learn about the effects of temperature on gas density and pressure in compressed systems.
  • Research safety mechanisms in pressurized gas systems, including valve operation and pressure thresholds.
  • Explore advanced thermodynamic calculations involving changes in state for gases.
USEFUL FOR

Students in physics or engineering, safety engineers, and professionals working with compressed gas systems will benefit from this discussion.

moenste
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Homework Statement


A cylinder containing 19 kg of comperessed air at pressure 9.5 times that of the atmosphere is kept in a store at 7 °C. When it is moved to a workshop where the temperature is 27 °C a safety valve on the cylinder operates, releasing some of the air. If the valve allows air to escape when the its pressure exceeds 10 times that of the atmosphere, calculate the mass of air that escapes.

Answer: 0.33 kg

2. The attempt at a solution
Density of air = 1.293 kg m-3

Mass = Volume * Density
VolumeStore = 19 / 1.293 = 14.7 m3

VWorkshop = (pStore * VStore * TWorkshop) / (TStore * pWorkshop) = (9.5 p0 * 14.7 * 300.15) / (280.15 * 10 p0) = 14.95 m3

MassWorkshop = 14.95 * 1.293 = 19.33 kg

19.33 - 19 = 0.33 kg... fits the answer but why the mass is 19.33 after the escape? What's wrong?
 
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moenste said:

Homework Statement


A cylinder containing 19 kg of comperessed air at pressure 9.5 times that of the atmosphere is kept in a store at 7 °C. When it is moved to a workshop where the temperature is 27 °C a safety valve on the cylinder operates, releasing some of the air. If the valve allows air to escape when the its pressure exceeds 10 times that of the atmosphere, calculate the mass of air that escapes.

Answer: 0.33 kg

2. The attempt at a solution
Density of air = 1.293 kg m-3

This appears to be the density of air at standard temperature and pressure. It's not clear how this relates to the problem.

When air is compressed to 9.5 times atmospheric pressure, its density increases.
Mass = Volume * Density
VolumeStore = 19 / 1.293 = 14.7 m3

The air is compressed and kept in a cylinder in a store, or storage room. It's not clear why you are calculating the volume of 19 kg of air at standard pressure and temperature. (See above)
VWorkshop = (pStore * VStore * TWorkshop) / (TStore * pWorkshop) = (9.5 p0 * 14.7 * 300.15) / (280.15 * 10 p0) = 14.95 m3

MassWorkshop = 14.95 * 1.293 = 19.33 kg

19.33 - 19 = 0.33 kg... fits the answer but why the mass is 19.33 after the escape? What's wrong?
Your approach to solving this problem is puzzling.
 
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moenste said:

Homework Statement


A cylinder containing 19 kg of comperessed air at pressure 9.5 times that of the atmosphere is kept in a store at 7 °C. When it is moved to a workshop where the temperature is 27 °C a safety valve on the cylinder operates, releasing some of the air. If the valve allows air to escape when the its pressure exceeds 10 times that of the atmosphere, calculate the mass of air that escapes.

Answer: 0.33 kg

2. The attempt at a solution
Density of air = 1.293 kg m-3

Mass = Volume * Density
VolumeStore = 19 / 1.293 = 14.7 m3

VWorkshop = (pStore * VStore * TWorkshop) / (TStore * pWorkshop) = (9.5 p0 * 14.7 * 300.15) / (280.15 * 10 p0) = 14.95 m3

MassWorkshop = 14.95 * 1.293 = 19.33 kg

19.33 - 19 = 0.33 kg... fits the answer but why the mass is 19.33 after the escape? What's wrong?

As far as the mass of air escaping from the cylinder is concerned, the pressure inside the workshop is immaterial, unless you assume the workshop is airtight, which few are.

The ambient temperature difference between the store room and the workshop is what is causing the air to want to expand inside the cylinder.

Concentrate on what is happening inside the compressed air cylinder. Use the perfect gas law, PV = nRT, to find out the details.
 
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