Mass of Hanging Rope: Calculate Easily

Click For Summary
SUMMARY

The mass of a hanging rope can be calculated using the catenary equation, provided that the tension at the lowest point (denoted as ##T_0##) is known. The catenary shape remains consistent across ropes of varying linear mass densities, but additional information, such as the tension, is essential for determining mass. To find the mass, one must derive the weight per unit length (##w_0##) from the tension and height (##h##), calculate the total length of the rope based on the horizontal distance (##d##), and then convert the weight to mass using gravitational acceleration (##g##).

PREREQUISITES
  • Understanding of catenary equations and their applications
  • Knowledge of tension in physics, specifically at suspension points
  • Familiarity with free body diagrams (FBD) for analyzing forces
  • Basic calculus for deriving slopes and lengths in the context of catenary functions
NEXT STEPS
  • Study the catenary equation and its derivation for different scenarios
  • Learn how to construct and interpret free body diagrams in physics
  • Research the relationship between tension, weight, and mass in hanging systems
  • Explore practical applications of weighted catenaries in engineering and architecture
USEFUL FOR

Students of physics, structural engineers, and anyone involved in projects requiring the calculation of hanging structures or ropes will benefit from this discussion.

Mark128
Messages
4
Reaction score
1
Hi, I have a question about a hanging rope - how do you find it's mass? I've been searching a long time, stumbled across some advanced calculus involving catenary functions and equations, but couldn't quite figure it out.
Bez tytułu.png
 
Physics news on Phys.org
If all that's given is ##h## and ##d## as shown in your figure, you cannot find its mass. The catenary shape will be the same if you hang ropes of different linear mass densities but equal lengths from the two points. You will need additional information such as the tension at the point of suspension to find the mass.
 
  • Like
Likes   Reactions: Lnewqban and vanhees71
It's been 50+ years since I did any catenary math but what you show is just a catenary. The shape is in no way dependent on the mass, assuming the mass is uniform throughout the rope (and if it isn't you probably wouldn't have a catenary anyway)

EDIT: I see kuruman beat me to it.
 
  • Like
Likes   Reactions: vanhees71
kuruman said:
If all that's given is h and d as shown in your figure, you cannot find its mass. The catenary shape will be the same if you hang ropes of different linear mass densities but equal lengths from the two points. You will need additional information such as the tension at the point of suspension to find the mass.
And if a tension at the lowest point is given? Then how to calculate its mass?
 
Mark128 said:
Hi, I have a question about a hanging rope - how do you find it's mass?
@Mark128 do you have a practical reason for asking this or are you just playing around with math. If you are playing around with math, then learn the math. If you have a practical reason, then consult a structural engineer to help with your project (and be very specific about exactly what you are doing, WITH numbers)
 
Mark128 said:
And if a tension at the lowest point is given? Then how to calculate its mass?

If you know the tension ##T_0## at the lowest point, then
  1. Use the catenary equation to find the slope ##\dfrac{dy}{dx}## at an arbitrary point.
  2. Find the length ##s## of a piece of rope from the lowest point to a point at an arbitrary value of ##x##.
  3. Draw a free body diagram of that piece. Note that if you let ##w_0## be the rope's weight per unit length, the weight of the piece of length ##s## is ##w_0s##.
  4. Use the FBD to find a relation ##w_0 =\dots## in terms of ##T_0## and ##h##.
  5. Find the total length of the rope in terms of ##h## and ##d## and multiply by your result for ##w_0## to find the weight of the rope.
  6. Divide by ##g## to get the mass.
##m=\dfrac{2T_0}{g}\sinh\left(\dfrac{d}{2h}\right).##
 

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 12 ·
Replies
12
Views
16K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 131 ·
5
Replies
131
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 67 ·
3
Replies
67
Views
6K