Mass of silver to cover a 2.0 x10^2 cm2 object with .20mm thick layer

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To determine the mass of silver needed to coat a 2.0 x 10^2 cm² object with a 0.20 mm thick layer, first calculate the volume of silver required by multiplying the surface area by the thickness. Convert the thickness from millimeters to centimeters for consistency, resulting in 0.02 cm. The volume is then found by multiplying the surface area (200 cm²) by the thickness (0.02 cm), yielding a volume of 4 cm³. Finally, use the density of silver (10.49 g/cm³) to find the mass by multiplying the volume by the density, resulting in a mass of approximately 41.96 grams. This calculation provides the total mass of silver required for the coating.
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Homework Statement



if an object to be coated in a .20mm thick layer with a surface area of 2.0x10^2 cm^2, what is the mass of the silver required? (density of silver is 10.49 g/cm^3)

Homework Equations



d=m/v , surface area formula? not sure which one


The Attempt at a Solution



i know i am to use the surface area and depth info to calculate the volume of silver required to plate the object, then use the density provided to convert it to grams..

but not sure where to start..
 
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geoti8 said:

The Attempt at a Solution



i know i am to use the surface area and depth info to calculate the volume of silver required to plate the object, then use the density provided to convert it to grams..

but not sure where to start..

Start where you said: use the surface area and depth info to calculate the volume.
 
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