A metal bar of mass m slides frictionlessly on two parallel conducting rails a distance l apart. A resistor R is connected across the rails and a uniform magnetic field B , pointing into the page , fills the entire region.
a) If the bar moves to the right at speed v, what is the current in the resistor? In what direction does it flow?
b) What is the magnetic force on the bar? In what direction?
c) If the bar starts out with the speed v0 at t=0 , and is left to slide , what is its speed at a later time t
d) the initial KE of the bar was , of course 1/2mv0^2. Check that the energy delivered to the resistor is exactly 1/2mv0^2.
The Attempt at a Solution
in this case h is l. Therefore emf=vBl
b) emf=closed integral(fmag*dl)=vBl. Not sure what dl is. I supposed it the length of the metal bar?
If so, then
Didn't really begin on c and d but I will ask about those problems later when I attempt to solved them.