Mass-spring system (not exactly homework)

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SUMMARY

The discussion focuses on the dynamics of a mass-spring system, specifically analyzing the forces acting on a mass, m, when stretched beyond its equilibrium position. The equation mg + (-kx0) = 0 establishes the relationship between mass, gravitational force, and spring constant, k. The derived equation of motion, a = -kx1/m, leads to the corollary ω0 = √(k/x), which describes the angular frequency of the system. The conversation emphasizes the importance of solving the differential equation to understand the system's behavior.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with Hooke's Law and spring constants
  • Basic knowledge of differential equations
  • Concept of angular frequency in oscillatory systems
NEXT STEPS
  • Study the derivation of the differential equation for harmonic motion
  • Explore solutions to second-order linear differential equations
  • Learn about the physical interpretation of angular frequency in oscillatory systems
  • Investigate the effects of damping on mass-spring systems
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Physics students, mechanical engineers, and anyone interested in the principles of oscillatory motion and mass-spring systems.

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Case of a spring with a mass,m, that has been stretch beyond the equilibrium in the positive x direction.

mg + (-kx0) = 0
k = mg/x0

stretch:

F = mg+ [-k(x0+x1)] = mg-kx0-kx1
but since mg-kx0 = 0
F = 0-kx1 = ma

ma = -kx1
a = -kx1/m

How do I arrive at the corollary from a = - kx1/m to ω0 = SQRT[k/x]?
 
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##a = -kx_1## can be expressed as ##d^2x / dt^2 = -kx_1##

Now it comes down to fitting a solution to this differential equation...
 

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