Mastering the 5 Kinematic Equations: An In-Depth Look at Motion Rules

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SUMMARY

The discussion centers on the five key kinematic equations used to describe motion: d = (vf + vi)/2 * t, vf = vi + at, d = vit + 1/2at^2, vf^2 = vi^2 + 2ad, and d = vft - 1/2at^2. Participants clarify that the equations d = 1/2(vi + vf)t and d = 1/2at^2 are derived forms, specifically applicable when initial velocity (vi) is zero. The consensus is that only two equations, vf = vi + at and d = vit + 1/2at^2, are essential for deriving the others. Understanding these equations is crucial for mastering kinematics in physics.

PREREQUISITES
  • Understanding of basic physics concepts such as velocity, acceleration, and displacement.
  • Familiarity with algebraic manipulation of equations.
  • Knowledge of calculus for deeper insights into motion equations.
  • Ability to apply kinematic equations to solve numerical problems in physics.
NEXT STEPS
  • Study the derivation of kinematic equations from basic principles of motion.
  • Learn how to apply the equations in real-world physics problems.
  • Explore the relationship between calculus and kinematics, particularly integration of acceleration.
  • Practice solving numerical problems using the five kinematic equations.
USEFUL FOR

Students of physics, educators teaching kinematics, and anyone looking to strengthen their understanding of motion equations and their applications in problem-solving.

harujina
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I know that there's 5 key equations for motion which is:

d = (vf+vi/2)t
vf = vi + at
d = vit + 1/2at^2
vf^2 = vi^2 + 2ad
d = vft - 1/2at^2

Correct?
But my teacher was confusing me today and he taught us these two other equations:

d = 1/2(vi+vf)t
d = 1/2at^2

What are these? Are they just other "rules of motion" like everything else?
 
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The second equation 'D=1/2at^2' is one of the kinematic equations 'D=Vi+1/2at^2' where the initial velocity 'Vi' is considered to be zero.
 
quawa99 said:
The second equation 'D=1/2at^2' is one of the kinematic equations 'D=Vi+1/2at^2' where the initial velocity 'Vi' is considered to be zero.
oh right, i can't believe i didn't notice that! ok thank you!
 
harujina said:
d = (vf+vi/2)t

This one is incorrect. Either your teacher or you copied it wrong.

d = 1/2(vi+vf)t

This is the correct version, assuming you meant (1/2)(vi+vf)t.

Actually, only two equations are essential:

vf = vi + at
d = vit + (1/2)at2

The others can be derived from these two.
 
5 eq

v final velocity
u initial vel.
t time
s displacement
a constant accn


v= u +at
s= ut + .5at2
v2= u2 +2as
s= vt - .5at2
s= .5(v+u)t
 
jtbell said:
This one is incorrect. Either your teacher or you copied it wrong.
This is the correct version, assuming you meant (1/2)(vi+vf)t.

Actually, only two equations are essential:

vf = vi + at
d = vit + (1/2)at2

The others can be derived from these two.

but while doing numerical it is irritating to first get acceleration, so actually 5 eqn
are good adding to it this gives feel to a child what he's doing
also kinematics it a beginning so one can learn these quickly as afterward formula formula formula!
 
jtbell said:
Actually, only two equations are essential:

vf = vi + at
d = vit + (1/2)at2

The others can be derived from these two.

You can chose any two out of the five to take as essential and derive the other three from them
 
True, but I like those two because if you know calculus you can get them by integrating d2x/dt2 = a twice. Of course, that means you really need to remember only one equation which basically just says "acceleration is constant." :biggrin:
 

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