Mastering the Chain Rule: A Quick Guide for Calculus Students

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Homework Help Overview

The discussion revolves around finding the derivative of the function y = 2x / (1+x^2)^2 using calculus techniques, specifically the chain rule and quotient rule.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of the chain rule and quotient rule, with some expressing confusion about their usage. There are attempts to reformulate the problem to avoid the quotient rule by suggesting the use of the product rule instead.

Discussion Status

Participants are actively discussing various methods to approach the problem, including the potential to use only the chain rule. Some guidance has been offered regarding the application of the product rule and reformulating the expression, but there is no explicit consensus on the best approach.

Contextual Notes

There is a mention of the original poster's uncertainty due to a lack of recent practice with calculus, which may be influencing their understanding of the rules involved.

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Homework Statement


y = 2x / (1+x^2)^2

Find dy/dx

Homework Equations


Chain rule


The Attempt at a Solution


I completely forgot how to apply the chain rule.. I mean, I can always apply the quotient rule, but I'm sure this is 1000 times easier if you can apply the chain rule. Do you do something like

u = 1+x^2
du = 2x

so

y = du/u

But I may be getting confused with substitution rule with integration.. it's been a while since I touched calculus.. any suggestions?
 
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Chain rule goes something like
dy/dx=dy/du*du/dv*...*df/dx .

It is usually used when you when you have a nested combination of functions, ie functions within functions.

For your question, you need to use both the quotient rule as well as the chain rule ( (1+x^2)^2, which is the funtion 1+x^2 within a squaring function ) .

Can you finish your problem now ?
 
arunbg said:
Chain rule goes something like
dy/dx=dy/du*du/dv*...*df/dx .

It is usually used when you when you have a nested combination of functions, ie functions within functions.

For your question, you need to use both the quotient rule as well as the chain rule ( (1+x^2)^2, which is the funtion 1+x^2 within a squaring function ) .

Can you finish your problem now ?

Right.. that's the BRUTE force way to do it.

I was wondering if there was a way to finish this without even applying the quotient rule
 
if you don't want to use the quotient rule you can bring the denominator up top so:[tex]y= 2x (1+x^2)^{-2}[/tex] now use the product rule
 
l46kok said:
Right.. that's the BRUTE force way to do it.

I was wondering if there was a way to finish this without even applying the quotient rule

Yes, just write the expression as 2x(1+x2)-2, and use the product rule on this.
 
suspenc3 said:
if you don't want to use the quotient rule you can bring the denominator up top so:[tex]y= 2x (1+x^2)^{-2}[/tex] now use the product rule

I guess that's true, but when I saw the relating terms, I was thinking this could be solved by ONLY using chain rule.

I guess it's impossible.
 

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