Math Contest Help: Get Reasonable Solutions & Explanations

  • Thread starter Thread starter ballaholic8
  • Start date Start date
  • Tags Tags
    Contest
AI Thread Summary
The discussion focuses on providing assistance for math contest preparation, emphasizing the importance of drawing diagrams for geometry problems to visualize angles and relationships. It explains the concept of polynomial division, specifically how to determine roots and factor quadratics, using the example of kx^2 - bx + k and the divisor 3x - 5. Participants are encouraged to identify similar triangles in geometric figures and utilize given information to construct relevant diagrams. Additionally, the conversation touches on rewriting functions in terms of new variables to simplify problem-solving. Overall, the thread aims to offer clear solutions and explanations for complex math problems.
ballaholic8
Messages
4
Reaction score
0
Hey guys I am preparing for a math contest and this is a review set that we have recieved, however i have no idea how to answer these questions,

Can someone please help with some reasonable solutions with some explanation.

Thanks
 

Attachments

  • 131 18-19.jpg
    131 18-19.jpg
    15.3 KB · Views: 423
  • 131 20.jpg
    131 20.jpg
    8.7 KB · Views: 432
  • 121 24-25.jpg
    121 24-25.jpg
    13.9 KB · Views: 441
Physics news on Phys.org
18. As in all geometry problems, draw a diagram. Draw in the angles you need to find. See if you can go from there.

19. What does it mean for 3x-5 to divide kx2-bx+k? It means that kx^2-bx+k=(3x-5)q(x) for some polynomial q(x). It also means that if we set 3x-5=0, then the original quadratic will be 0 too. That is, when x = 5/3, kx2-bx+k=0, so 5/3 is a root of the quadratic. Every quadratic can be factored as follows: ax^2+bx+c=a(x-r_1)(x-r_2) where r1 and r2 are the two roots of the quadratic. Thus, you can write kx^2-bx+k=k(x-5/3)(x-r_2). Multiply out and find out what r2 must be. You then can find k/b.

20. Which triangles are similar in that picture?

24. Again, draw a picture (this is a common theme in geometry problems), and try to draw a triangle using the information you have available.

25. Suppose y=x^2+2. Then, you can rewrite g(x^2+2) in terms of y, so you would have g(y) = some function of y. Notice then that g(x^2-1) is merely g(y-3).
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

Similar threads

Replies
2
Views
2K
Replies
4
Views
2K
Replies
15
Views
2K
Replies
13
Views
2K
Replies
12
Views
2K
Replies
21
Views
3K
Replies
19
Views
2K
Back
Top