Math Induction: Where Does the >2xk Come From?

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Discussion Overview

The discussion revolves around the mathematical concept of induction, specifically questioning the origin and implications of the expression > 2 x k in relation to the proposition being examined. Participants explore the validity of the proposition and its relationship to k and k+1.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant questions the origin of the expression > 2 x k, suggesting it should be > k+1 based on the proposition.
  • Another participant points to a previous line in the discussion to clarify the context of the questioned statement.
  • A participant expresses confusion about the validity of the proposition, noting that 2^(k+1) is equal to or greater than k+1, raising concerns about its truth in that case.
  • One participant argues that if k > 1, then 2k > k + 1, indicating a specific condition under which the proposition holds.
  • Another participant reiterates the concern about the relationship between 2^(k+1) and k+1, questioning how the proposition can be considered true under those conditions.
  • A later reply attempts to clarify that the proposition is true because it states 2^(k+1) > k + k, which is greater than or equal to k+1, thus supporting the proposition.

Areas of Agreement / Disagreement

Participants express differing views on the validity of the proposition and its implications, indicating that multiple competing perspectives remain unresolved.

Contextual Notes

The discussion highlights potential limitations in understanding the relationship between the expressions involved, particularly regarding the conditions under which the proposition is claimed to be true.

coconut62
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Please refer to the image attached.

Where does the > 2 x k come from?

Based on the proposition, shouldn't it be > k+1?
 

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look two lines above the questioned statement.
 
I got it, thanks.
 
But one more thing: 2^(k+1) is equal or bigger than k+1. Then it's not necessarily bigger than k+1. How can we say that the proposition is true for that case?
 
coconut62 said:
But one more thing: 2^(k+1) is equal or bigger than k+1. Then it's not necessarily bigger than k+1. How can we say that the proposition is true for that case?
If k > 1, then 2k > k + 1.

2k = k + 1 only if k = 1.
 
Greater and Greater-Equal

coconut62 said:
But one more thing: 2^(k+1) is equal or bigger than k+1. Then it's not necessarily bigger than k+1. How can we say that the proposition is true for that case?


The propisition is true since it says 2^{k+1} > k + k \ge k+1 and together 2^{k+1} > k+1.
 

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