Matlab - multiple integral Riemann sums

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The discussion focuses on creating a MATLAB function to compute the double integral of a function f(x, y) over a specified rectangle, using Riemann sums. The user has shared their current implementation but is facing issues with convergence, as the function does not achieve the desired relative error within the maximum iteration limit of 100. Feedback suggests that the increment of the Riemann sum's subdivisions (n) should be increased more significantly, such as doubling n each iteration, to improve convergence speed. The user is also advised to ensure the error-catching mechanism for divergent integrals is functioning correctly. Overall, the conversation revolves around debugging and optimizing the Riemann sum calculation in MATLAB.
mathmannn
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1. Homework Statement

Write an m.file that will integrate a function f(x, y) on any given rectangle (a,b)\times(c,d) and returns the value of the integral from a to b and c to d of the function f(x,y). Include error-catching code in the case that the integral diverges. The program should use the notion of a limit of sums, so that you increase the number of Riemann cubes until the approximate value of the integral shows a relative error \displaystyle \frac{S_{new} - S_{old}}{S_{new}} of less than 0.001.


Homework Equations





The Attempt at a Solution



Ok so here is what I have right now
Code:
function [re,risum]=ftc3(f,a,b,c,d,maxit)
% ftc3: Finds the riemann Sum for the function f
% input:
% f = function, a = x lower bound, b = x upper bound
% c = y lower bound, d = y upper bound
% output:
% re = relative error, risum = value of the definite integral

% Note:
%       The 'maxit' input is just something I'm using so 
%       I don't get stuck in a loop.

if nargin<6|isempty(maxit),maxit=100;end
err=1;
s=0;
n=1;
its=0;
fprintf('\nn\t error\t   dx\t   dy\t   dA\t  sum\n\n');
while(1)
    s0=s;
    dx=(b-a)/n;
    dy=(d-c)/n;
    xi=a+dx:dx:b;
    yi=c+dy:dy:d;
    dA=dx*dy;
    s=sum(f(xi,yi))*dA;
    if s>realmax,error('This integral diverges');end
    rerr = abs((s-s0)/s);
% Note:    
%       I'm just using this table so I can see what
%       is going on with my code. It's not needed for the problem
    z=[n;rerr;dx;dy;dA;s];
    fprintf('%d\t %2.4f\t %2.4f\t %2.4f\t %2.4f\t %2.4f\n',z);
    its=its+1;
    n=n+1;
    if rerr<.001|its>=maxit,break,end
    
end
risum=s;
re = rerr;
disp(['Number of iterations ',num2str(its)])
but I can not figure out what is wrong with my code. When I test it using \int_0^1 \int_0^1 xy \quad dx dy which I know should be \frac{1}{4}

This is what it returns (without the table)
Code:
EDU>> f=@(x,y) x.*y;a=0;b=1;c=0;d=1;
EDU>> [relative_error,riemann_sum]=ftc3(f,a,b,c,d)
Number of iterations 100

relative_error =

    0.0103


riemann_sum =

    0.0034


Any kind of help would be awesome!
 
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You have three possible exit conditions for your loop. One is a divergence catch, which isn't an issue here. The second is achieved convergence, and the third is if the number of iterations exceeds the number "itmax." You have set this maximum at 100, and clearly it's taking 100 iterations, which means it hasn't converged because it's reached that limit and not gotten within the desired error yet. I am guessing the reason you don't reach convergence within 100 steps is that you are only increasing n by one each time. Probably a better strategy is to double it with each iteration.
 

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