Matrices of simple face and cubic centered cubic lattice

  • Context: Graduate 
  • Thread starter Thread starter Petar Mali
  • Start date Start date
  • Tags Tags
    Cubic Lattice Matrices
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 4K views
Petar Mali
Messages
283
Reaction score
0
[tex]S=<br /> \begin{bmatrix} a & 0 & 0 \\ 0 & a & 0 \\ 0 & 0 & a \end{bmatrix}[/tex]

for simple cubic


[tex]I=<br /> \begin{bmatrix} -\frac{a}{2} & \frac{a}{2} & \frac{a}{2} \\ \frac{a}{2} & -\frac{a}{2} & \frac{a}{2} \\ \frac{a}{2} & \frac{a}{2} & -\frac{a}{2} \end{bmatrix}[/tex]

for volume centered cubic

[tex]F=<br /> \begin{bmatrix} 0 & \frac{a}{2} & \frac{a}{2} \\ \frac{a}{2} & 0 & \frac{a}{2} \\ \frac{a}{2} & \frac{a}{2} & 0 \end{bmatrix}[/tex]

for face centered cubic

I don't see any logic for this matrices? How can I get this? I can axcept that simple is P because minimum distance between neighbors is [tex]a[/tex]. But But what with the other two matrices?
 
Physics news on Phys.org
Those matrices have the lattice vectors as rows (or columns, since they are symmetric). If you have a cube with side length a and one corner at the origin, then integer combinations of those vectors give you the lattice points. I'm not sure what your question is. Look at FCC. You have one atom at each corner, so points like (a,0,0) and (0,a,0), etc. Then at the center of each face, so points like (a/2,a/2,0) and (a/2,0,a/2). Those points come from adding those vectors together.