Matrix of a Linear Transformation Example

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The discussion revolves around understanding a linear transformation example related to coordinate isomorphism between bases. The user is confused about how the transformation results differ from the standard basis, particularly with the vectors [1,0,0] and [1,1,0] yielding unexpected outputs. There is a suggestion to compute the matrix representing the transformation to clarify these discrepancies. The user is encouraged to apply this matrix to specific vectors to better understand the results. Overall, the conversation aims to elucidate the relationship between different bases and their transformations in linear algebra.
~Sam~
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Homework Statement


Hi this isn't really a question but more so understanding an example that was given to me that I not know how it came to it's conclusion. This is a question pertaining linear transformation for coordinate isomorphism between basis.
https://imgur.com/a/UwuAC

Homework Equations


Here is some of the preceding material:
https://imgur.com/a/acpyU

The Attempt at a Solution


I'm not sure how it came to it's conclusion for the basis G, for example the vector [1,0,0] doesn't yield the same result as the standard basis, but gets [1,-2,2] instead even though it is a standard basis e1. I thought for [1,1,0] in G the result would be [1,1,2] but instead it's [-1,1,0]. I've tried working backwards from the solution but that hasn't helped. Can anyone help me understand this?[/B]
 
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First thing, do you know how to compute the matrix representing ##C_G##?

Once you have the matrix for ##C_G##, you can compute (for example) ##C_G(T(1))=C_G\begin{pmatrix}1\\0\\2 \end{pmatrix}## and see why it "doesn't yield the same result as the standard basis".
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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