Max Collector Current in Transistor Circuits

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To calculate the maximum collector current (Ic_max) in transistor circuits, the source voltage is essential for determining the base current (Ib) using the equation Ic = BIb. The discussion highlights the need to consider saturation mode, where the collector-emitter voltage (Vce) is at its lowest, typically around 0.2V. A correction was made regarding the voltage drop, adjusting Vce to 8V, leading to the calculation of Ic_max as 9.8mA using the formula Ic_max = (10V - 0.2V) / 1000 ohms. The conversation emphasizes understanding the relationship between Vce and Ic in different operating modes. The final conclusion confirms the calculation of Ic_max was successfully resolved.
Marcin H
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Homework Statement


Calculate the max collector current.

Homework Equations


Ic=BIb
V=IR

The Attempt at a Solution


I'm not sure how to find the max collector current. Don't I need the source voltage to find my Ib and then use that to find my Ic? Is there another way of finding Ic_max? Also, are B,C,D done correctly? I feel like D is wrong because of the huge voltage. (sorry about the bad scan. Had to use phone)
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a. it says max POSSIBLE collector current. how high can Vce go?
b. & c. OK
d. can Ic exceed 10V/1K?
 
rude man said:
a. it says max POSSIBLE collector current. how high can Vce go?
b. & c. OK
d. can Ic exceed 10V/1K?
Just noticed the 2A error in my calculation for D. Should be 8V for Vce. And for A I'm not sure. I think the max possible collector current would happen in saturation mode. So does that mean Vce=Vce(sat)? So Vce would be 0.2V?
 
Marcin H said:
Just noticed the 2A error in my calculation for D. Should be 8V for Vce. And for A I'm not sure. I think the max possible collector current would happen in saturation mode. So does that mean Vce=Vce(sat)? So Vce would be 0.2V?
Icmax=(10V-0.2V)/1000ohms = 9.8mA. Never mind. Got it :)
 
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