What Is the Maximum Error in an 8-bit ADC with a Full Scale Input of 2.55V?

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SUMMARY

The maximum error in an 8-bit ADC with a full-scale input of 2.55V is determined to be 12.55mV when considering both quantization error and cumulative errors. The quantization error, calculated as ε Max = 2.55V / (2^8), equals 10mV. Adding the cumulative error of 2.55mV results in a total maximum error of 12.55mV. If quantization error is not included in the cumulative errors, the maximum error would be 7.55mV, but this scenario is not applicable in this context.

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Homework Statement


An 8 bit ADC has a full scale input of 2.55V. If other cumulative errors are 2.55mV, determine the maximum error.

Options are: 10mV, 2.55mV, 12.55mV, 7.45mV

Homework Equations


I believe this is a conceptual question. The only equation I can come up with is that the quantization error in an ADC is at max, half of LSB.

The Attempt at a Solution


Assuming cumulative errors as mentioned in the question does not include quantization error (LSB/2),
maximum error
= Q error + C error
=5mV + 2.55mV
= 7.55mV

If cumulative errors include Q error, then max error = 2.55mV as the other errors that can creep into an ADC are non-linearity and aperture errors, both of which more data to calculate.
 
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asp_physics said:

Homework Statement


An 8 bit ADC has a full scale input of 2.55V. If other cumulative errors are 2.55mV, determine the maximum error.

Options are: 10mV, 2.55mV, 12.55mV, 7.45mV


Homework Equations


I believe this is a conceptual question. The only equation I can come up with is that the quantization error in an ADC is at max, half of LSB.


The Attempt at a Solution


Assuming cumulative errors as mentioned in the question does not include quantization error (LSB/2),
maximum error
= Q error + C error
=5mV + 2.55mV
= 7.55mV

If cumulative errors include Q error, then max error = 2.55mV as the other errors that can creep into an ADC are non-linearity and aperture errors, both of which more data to calculate.

I think your solution is correct. Half of an LSB plus the other error...
 
There is no such ans like 7.55mv.
I think...
Quantization Error is (ε Max)= 2.55v/(2^8)=10 mv
so total error = 10mv+2.55mv = 12.55 mv(Correct Ans)

As per ur concept," if Qunts. error contain in 2.55mv other Cumulative error " which is not possible.

10-2.55 =7.45 mv(not the Ans)
 
Last edited:
Although you might think an ADC module should be designed to have a quantization error of ½LSB, in practice it may be the case that max quantization error = LSB. This comes about by max input (corresponding to output=11111111) being 127/128 Vref.
 

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