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## Homework Statement

An object is shot vertically upward and has a speed of 12 m/s when it reaches one fifth of its maximum height.

a. What is the initial speed of the object?

b. What is the maximum height of the object?

## Homework Equations

Free falling objects

## The Attempt at a Solution

I used the formula vf^2 = vi^2 - 2g(yf - yi) and got 144 = 0 + 19.6(1/5 - 0), I solved for 1/5 so I have 144/19.6 = 1/5 and got 1/5 = 7.35 meters. This times 5 yields 36.73 meters. This would be it for part b. But I am stuck on part a where I have to find the speed. Any advise on how to approach this? Thank you.