An object is shot vertically upward and has a speed of 12 m/s when it reaches one fifth of its maximum height.
a. What is the initial speed of the object?
b. What is the maximum height of the object?
Free falling objects
The Attempt at a Solution
I used the formula vf^2 = vi^2 - 2g(yf - yi) and got 144 = 0 + 19.6(1/5 - 0), I solved for 1/5 so I have 144/19.6 = 1/5 and got 1/5 = 7.35 meters. This times 5 yields 36.73 meters. This would be it for part b. But I am stuck on part a where I have to find the speed. Any advise on how to approach this? Thank you.