Max speed of proton in cyclotron

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SUMMARY

The maximum speed of a proton in a cyclotron is established at 5.17 x 107 m/s, occurring within a magnetic field strength of 0.450 T and a radius of 1.20 m. The discussion clarifies that protons are accelerated in a cyclotron, causing their orbital radius to increase until they escape the magnetic field. The confusion regarding the escape of protons is addressed by explaining that the magnetic force provides centripetal force, but the radius of the orbit increases as protons gain energy. Understanding the cyclotron principle eliminates the need to calculate the electric force on protons, as it can be inferred from the magnetic field strength and cyclotron frequency.

PREREQUISITES
  • Cyclotron principles and operation
  • Magnetic field strength and its effects on charged particles
  • Understanding of centripetal force in circular motion
  • Basic knowledge of proton acceleration in particle physics
NEXT STEPS
  • Research the mathematical derivation of proton speed in a cyclotron
  • Explore the relationship between magnetic field strength and particle acceleration
  • Learn about the cyclotron frequency and its implications in particle physics
  • Investigate the conditions under which protons escape the magnetic field in a cyclotron
USEFUL FOR

Physics students, particle physicists, and engineers working with particle accelerators will benefit from this discussion, particularly those interested in the dynamics of charged particles in magnetic fields.

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Homework Statement
Please see below
Relevant Equations
Please see below
For this problem,
1674690491201.png

The solution is,
1674690074014.png

However, I don't understand why they say just before the proton escapes? Are they assuming that the B-field is only at a portion of region which means that only half or so of the circular path is within the B-field so only half of the path have a magnetic centripetal force?

If the B-field is only there for a portion of the protons path, how do they know that max speed is reached?

Many thanks!
 
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The say "just before the proton escapes" to give you indirectly a numerical value. Which of the two values in the statement of the problem do you think that is?
 
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kuruman said:
The say "just before the proton escapes" to give you indirectly a numerical value. Which of the two values in the statement of the problem do you think that is?
The max speed is ##5.17 \times 10^7 \frac {m}{s}##?
 
Callumnc1 said:
The max speed is ##5.17 \times 10^7 \frac {m}{s}##?
I said the "in statement of the problem", not in the solution that follows it.
 
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kuruman said:
I said the "in statement of the problem", not in the solution that follows it.
Oh I see - thanks @kuruman!

It means max speed of proton over region of radius 1.20 m with B-field strength of 0.450 T.

EDIT: However, I still don't see how the proton would escape since theoretically it should continue moving in the circle of radius 1.20 m as the magnetic force provides the centripetal force. What would cause it to leave the B-field?
 
Protons in a cyclotron are accelerated. This means that the radius of the orbit increases until they escape. Look it up here to see how it's done.
 
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kuruman said:
Protons in a cyclotron are accelerated. This means that the radius of the orbit increases until they escape. Look it up here to see how it's done.
Thanks @kuruman , will do!
 
Callumnc1 said:
Thanks @kuruman , will do!
Ah so understanding the cyclotron principle I see now that you don't have to calculate the electric force on the protons going from each dee as that info can be gauged from the magnetic field strength and cyclon frequency that does not depend on radius.
 

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