Cyclotron Radius of Proton: .625m

[Noreturn]

Homework Statement

The cyclotron radius of a proton moving at 3.0*10^5 m/s perpendicular to a 5*10^-6T magnetic filed is:

Homework Equations

r=mv/qB

The Attempt at a Solution

So plug and chug:

r= (1.6*10^-27)(3*10^5)/(1.602*10^19)(5*10^-6)

r=625.5m

However they have it down as .625m. Where do I get the sig figs wrong at?

 

[kuruman]

Check the input numbers. The magnetic field looks awfully small for a cyclotron magnet and is close to the Earth's magnetic field.

 

[Noreturn]

I just checked the problem again and looks like I still did it right. Is it maybe just possible they messed up, or is the answer indeed .625?

 

[mfb]

Your answer is right.

The extremely low magnetic field (1/10 the magnetic field of Earth) suggests that they originally wanted to ask about 5*10^-3 T and then changed it without changing the answer.