- #36

Davidllerenav

- 424

- 14

I asked my teacher today. He said that indeed it start ar rest and accelerates at a and at somep point it decelerate at a in order to be at rest at B. He said that there arte two cases and that I need to choose one and explain why. So yes, I can use SUVAT equations. Which are the two cases?CWatters said:You seem to be making this problem much harder than it is. I very much doubt they intended you to think about limitations due to the speed of light!

It starts from A at rest and accelerates at "a". At some point it must stop accelerating and start to decelerate at "a" in order to be at rest at B.

A few basic equations of motion (eg SUVAT) and you are done.