Max Speed to Move from Point A to Point B

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Homework Help Overview

The problem involves determining the maximum speed an object must reach to travel from point A to point B in the least time possible, given a fixed acceleration and the option to move at a constant speed. The distance between the points is denoted as L.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the problem statement, questioning the clarity of the wording and whether it implies starting from rest. There is exploration of the implications of constant acceleration versus constant speed, and whether the object can switch between these modes of motion.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem's assumptions and parameters. Some suggest that the question may require additional constraints to make it reasonable, while others explore the potential use of kinematic equations versus calculus.

Contextual Notes

There is uncertainty regarding whether the object must start or finish at rest, and whether relativity should be considered in the context of maximum speed. Participants express confusion over terminology related to kinematics and dynamics, indicating a need for clearer definitions.

Davidllerenav
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Hi, I need help with this problem:

Homework Statement


Condition: an object has to move from point A to point B in the least time possible. The distance between the points is L. The object can accelerate (decelerate) with a fixed acceleration ##a## or move with a constant speed.

What maximum speed does this object have to reach to satisfy the condition?

Homework Equations


I guess this one:
##v= \frac {ds}{dt}##

The Attempt at a Solution


If the object moves from A to B in the least time possible, that means that ##\Delta t## tends to ##0##. To find the maximum speed I need to find the moment when the object travels more dinstance in the least time. That would be the derivative of the distance ##L## with respect to ##t##, so ##lim_{\Delta t\to 0} \frac{\Delta L} {\Delta t} = \frac {dL} {dt}##. Am I right? The problem is that I don't know hot to find the maximum speed necessary. How do I find the maximum speed?
 
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Davidllerenav said:
The object can accelerate (decelerate) with a fixed acceleration to or move with a constant speed.
The question makes no sense to me. Is this the exact wording? Is it a translation?
 
haruspex said:
The question makes no sense to me. Is this the exact wording? Is it a translation?
It is a translation. It is ##a## instead of "to". So it would be "The object can accelerate (decelerate) with a fixed acceleration ##a## or move with a constant speed."
 
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Davidllerenav said:
It is a translation. It is ##a## instead of "to". So it would be "The object can accelerate (decelerate) with a fixed acceleration ##a## or move with a constant speed."
Any constant speed or a given one? Is relativity to be taken into account?
 
haruspex said:
Any constant speed or a given one? Is relativity to be taken into account?
No costant speed. What do you mean with relativity?
 
Davidllerenav said:
No costant speed. What do you mean with relativity?
Are we limited to the speed of light?
 
haruspex said:
Are we limited to the speed of light?
Relativity is definitely out of the picture here.
 
Davidllerenav said:
No costant speed.
Sorry, I do not understand that answer. We are told we can use the constant acceleration, a, or a constant speed. Or does it mean the object can switch between the two, having started from rest?
 
Davidllerenav said:
Yes. Relativity is definitely out of the picture here.
If relativity is not assumed then the answer is no, we are not limited to the speed of light.
 
  • #10
haruspex said:
Sorry, I do not understand that answer. We are told we can use the constant acceleration, a, or a constant speed. Or does it mean the object can switch between the two, having started from rest?
That's a good question. I guess that it meas that we can use the constant acceleration or the constant speed, since it doesn't say anithing about it starting from rest.
 
  • #11
Davidllerenav said:
That's a good question. I guess that it meas that we can use the constant acceleration or the constant speed, since it doesn't say anithing about it starting from rest.
I'm struggling to find an interpretation that makes for a reasonable question. It seems obvious just to say go at an infinite speed.

If the choice is between
(1) a given acceleration, a, starting from rest and
(2) a given constant speed v
then it will depend on the numeric relationship between a, v and L.

Maybe you have to start and finish at rest, and you can mix accelerating at a, decelerating at a, and moving at constant speed.
 
  • #12
haruspex said:
I'm struggling to find an interpretation that makes for a reasonable question. It seems obvious just to say go at an infinite speed.
Why is it obvious? Wouldn't it be a non-constant speed then?
haruspex said:
If the choice is between
(1) a given acceleration, a, starting from rest and
(2) a given constant speed v
then it will depend on the numeric relationship between a, v and L.

Maybe you have to start and finish at rest, and you can mix accelerating at a, decelerating at a, and moving at constant speed.
I really don't know, I guess that it can start at rest, but why would it finish at rest?
 
  • #13
Davidllerenav said:
Why is it obvious? Wouldn't it be a non-constant speed then?
If it does not have to start at rest then you can start at the dedired speed. If you rule out an infinite speed there is no answer, because whatever speed you pick you can do better by going faster.
Davidllerenav said:
why would it finish at rest?
I am suggesting that as a requirement in order to make it a reasonable question.
 
  • #14
I agree. Question as written is too obvious. To turn it into a sensible question you must assume it starts or finishes at rest and its most likely they meant you to assume both. So the trip must be divided into three parts...

Acceleration at a
Constant velocity
Deceleration at -aYou need to work out how long each part should be to make the trip in the shortest time, and write an equation for the Max velocity achieved.
 
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  • #15
haruspex said:
If it does not have to start at rest then you can start at the dedired speed. If you rule out an infinite speed there is no answer, because whatever speed you pick you can do better by going faster.

I am suggesting that as a requirement in order to make it a reasonable question.
What about if relativity is considered? If the object can't go with infinite speed.
 
  • #16
I would suggest clarification from the teacher. Like, lots of clarification and highly suggested.

Also, is the answer to be found using calculus? or would simple kinematic equations do.
 
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  • #17
hmmm27 said:
I would suggest clarification from the teacher. Like, lots of clarification and highly suggested.

Also, is the answer to be found using calculus? or would simple kinematic equations do.
I guess kinematics. Since the last topic we saw was Galilean transformation.
 
  • #18
hmmm27 said:
Also, is the answer to be found using calculus? or would simple kinematic equations do.
Whatever the intent, calculus would be overkill.
And you mean kinetics; kinematics is something else.
 
  • #19
haruspex said:
Whatever the intent, calculus would be overkill.
Unless it was a math, not physics, class.
And you mean kinetics; kinematics is something else.
o:) LOL, I was wondering about that the other day : apologies for adding to existing confusion.

Wait, what ?:wideeyed:
 
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  • #20
hmmm27 said:
Unless it was a math, not physics, class.

o:) LOL, I was wondering about that the other day : apologies for adding to existing confusion.

Wait, what ?
Kinematics is not concerned with masses or forces. It is sometimes described as the geometry of motion. E.g. in a mechanical linkage it addresses how the components are constrained to move in relation to each other.
 
  • #21
The OP's question appears to be easily solveable (once the missing bits are found) with "kinematics equations", found in Wikipedia or our own reference post : time, distance, velocity (and acceleration).
 
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  • #22
haruspex said:
Kinematics is not concerned with masses or forces. It is sometimes described as the geometry of motion. E.g. in a mechanical linkage it addresses how the components are constrained to move in relation to each other.
But I think that we need to use kinematics, because we haven't see dynamics yet. Kinectics and dynamics are the same, right?
 
  • #23
Davidllerenav said:
But I think that we need to use kinematics, because we haven't see dynamics yet. Kinectics and dynamics are the same, right?
I erred.
I am used to people referring to kinematics in the context of questions involving accelerations resulting from torques and forces. In the present case, we are unconcerned with such - it is purely a question of the relationships between position, velocity, acceleration and time.
 
  • #24
haruspex said:
I erred.
I am used to people referring to kinematics in the context of questions involving accelerations resulting from torques and forces. In the present case, we are unconcerned with such - it is purely a question of the relationships between position, velocity, acceleration and time.
Exactly. So, If the answer would be infinite speed with no relativity. If now we are limited by speed of light, what would be the answer?
 
  • #25
Davidllerenav said:
Exactly. So, If the answer would be infinite speed with no relativity. If now we are limited by speed of light, what would be the answer?
I think you can make a stab at that.
 
  • #26
haruspex said:
I think you can make a stab at that.
I guess that it would be when it is near B, because it is under constant acceleration.
 
  • #27
Davidllerenav said:
I guess that it would be when it is near B, because it is under constant acceleration.
When what is near B? When A is near B? A and B are given, you can't move them.
It is a very simple question - if you want to get there ASAP, and your speed is limited only by the speed of light, what speed do you have to go at (as near as possible)?
 
  • #28
haruspex said:
When what is near B? When A is near B? A and B are given, you can't move them.
It is a very simple question - if you want to get there ASAP, and your speed is limited only by the speed of light, what speed do you have to go at (as near as possible)?
When the object moving from A to B is near B, because it is under a constant acceleration.
To answer your question, it would be as near as the speed of light.
 
  • #29
Davidllerenav said:
When the object moving from A to B is near B, because it is under a constant acceleration.
Sorry, but I have no idea what you are trying to say.
Davidllerenav said:
To answer your question, it would be as near as [possible to] the speed of light.
Yes.
 
  • #30
haruspex said:
Sorry, but I have no idea what you are trying to say.
I'll try to explain myself better. The objecc is moving from A to B, starting at rest with a constant acceleration a until it reaches B. So the fastest the object will be traveling would be when it gets to point B.
 

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