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## Homework Statement

A curve y = y(x) meets the x-axis at x = a, x = -a and has fixed length pi*a between these points. Show that the curve which encloses the maximum area between itself and the x-axis is the semi circle x^2 + y^2 = a^2 for y => 0

## Homework Equations

INT[-a,a] ds = INT[-a,a] (1 + (dy/dx)^2)^(1/2) = pi*a

y(a) = y(-a) = 0

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