Maximizing Cone Volume Inside a Sphere

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The discussion focuses on finding the dimensions of a right circular cone that maximizes volume within a sphere of radius 15 cm. The volume formula derived is V = (1/3)πr²(√(225 - r²) + 15), leading to a polynomial equation for r. The calculations resulted in r being approximately 11.5 cm and the height h around 24.63 cm. The maximum volume computed is approximately 3411.05 cm³. Confirmation of these dimensions and volume is sought from other participants.
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Homework Statement


Find the dimensions of the right circular cone of maximum volume that can be inscribed in a sphere of radius 15cm.

Homework Equations


The Attempt at a Solution



let r be radius of circular base of cone
let y be height of small right triangle
let h be height of cone
r^2 + y^2=225
y=sqrt(225-r^2)

h=15+y

V=(1/3)pir^2(sqrt(225-r^2) + 15)

Now to find V'...I get to 9r^4-2670r^2+195750 = 0
0=3(3r^4-890r^2+65250)

Need to solve for r.

Took about 2323 lines.

Final dimensions; r=11.5 roughly

h=24.63

maax volume is 3411.05 ?
 
Last edited:
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Can somebody confirm this? Thank you :)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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