Maximizing Velocity in Uniformly Accelerated Motion

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Homework Help Overview

The problem involves a car's motion between two traffic lights, focusing on uniformly accelerated motion and the calculation of maximum velocity reached during the journey. The car accelerates for a period, travels at a constant velocity, and then decelerates, with specific distances and times provided.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of a velocity-time graph to analyze the motion, questioning how to derive the maximum velocity given limited information about initial conditions.

Discussion Status

Some participants have offered guidance on using the area under the velocity-time graph to find the distance traveled, while others express uncertainty about how to proceed without an initial velocity. The discussion reflects a mix of attempts to clarify concepts and explore different interpretations of the problem.

Contextual Notes

Participants note the constraints of the problem, including the lack of initial velocity and the need to rely on time and total distance for calculations. The original poster expresses frustration but remains engaged in the problem-solving process.

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Homework Statement


a car takes 3 mins to travel between 2 sets of traffic lights which are 1800m apart, its velocity at each set of lights is 0ms-1

If the car accelerated uniformly for 30 secs and then maintained a constant velocity for the next 2 mins before retarding uniformly, calculate the the maxumum uniform velocity reached.

Homework Equations



usual suvat

The Attempt at a Solution

 
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It's probably best done drawing a velocity time graph and using the fact that the area under the graph is the distance travelled.
Have you tried that?
 
Thanks for the quick reply.

Yes I have looked at that but as I didnt have a velocity it seemed useless.

I think I'm struggling as there is only 2 components to use i.e. time and total distance.

I'll keep trying :)

cheers
 
The shape of the graph is a trapezium. If you know the formula for its area you have all you need to find the "height" of it. (Height= maximum velocity of car)
If you don't know the formula, treat the graph as 2 triangles and a rectangle and write down the area of each of those 3 shapes in term of the "height" of the graph.
Triangle area is half base times height. Rectangle is length times height.
 
Yip, that done it...lol thanks a lot for your help, it has cheers me up after a freak out earlier. I think I've been looking into further than was needed.

Thanks again,

Jeff
 

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