I Maximum Angle of Deflection for Colliding Particles

AI Thread Summary
In collisions between a heavier mass and a lighter one, the maximum angle of deflection is theoretically defined by the equation sin(θ_d_max) = m/M, where m is the mass of the lighter particle and M is the mass of the heavier one. The discussion raises questions about the physical mechanisms that dictate this maximum angle and the transition from grazing to non-grazing collisions. It highlights that the momentum in the center of mass system is equal and opposite, but the velocities differ, with the incoming mass influencing the center of mass velocity and limiting the scattering angle. The inquiry seeks a clearer understanding of the physical conditions that occur at the maximum angle of deflection. Overall, the conversation emphasizes the need for a deeper exploration of the dynamics involved in these collision scenarios.
neilparker62
Science Advisor
Homework Helper
Insights Author
Messages
1,191
Reaction score
683
TL;DR Summary
Trying to understand physics of maximum deflection
When a heavier mass (or nucleus say) collides with a lighter one, it deflects through a certain angle which has a theoretical maximum. There are numerous derivations for this maximum angle of deflection ##(\sin\theta_{d_{max}}=m/M)## where m is the small mass and M the larger but none seem to provide a clear physical explanation of what is going on. I tried to understand it in terms of energy transfer but got nowhere with that. So my question is what is physically going on when we reach maximum angle of deflection ? Is there something that physically defines when we move from a 'grazing' collision to a 'non grazing' collision ? Here for example is a plot of ##\tan\theta_d## vs ##\theta_i## where the latter angle of incidence is measured from the plane of contact. The mass ratio m/M in this case is 0.6 and so ##\theta_{d_{max}}=36.87^{\circ}## when ##\theta_i=63.42^{\circ}.##

1635184873136.png
 
Last edited:
Physics news on Phys.org
Below is a diagram that shows why the angle that the incoming body is scattered is always limited when its mass is greater than the target body's mass. The momenta of the two bodies are equal and opposite in the center of mass system but the velocities are not. The incoming mass dominates the velocity of the center of mass. Since the momentum of the incoming body in the center of mass system cannot be greater than 90° going to the lab system the center of mass velocity further increases its velocity reducing the scattering angle.

max scatt angle is limited..png
 
Thanks. I more or less understand why the angle of deflection is limited but I am trying to understand the exact physical conditions which are met when we reach the maximum angle.
 
neilparker62 said:
Thanks. I more or less understand why the angle of deflection is limited but I am trying to understand the exact physical conditions which are met when we reach the maximum angle.
Are you looking for some kind of rule like "when a projectile reaches maximum height its gravitational potential energy is maximum"?
 
Yes. Perhaps I'm missing something really obvious ?!
 
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Back
Top