Maximum angle of inclined plane before falling off the plane

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Discussion Overview

The discussion revolves around determining the maximum angle of an inclined plane before an object falls off, considering factors such as mass, height, and the coefficient of friction. The scope includes theoretical modeling and the mechanics of sliding and toppling.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant proposes a model involving mass, height, and coefficient of friction to find the angle at which torque from the center of mass overcomes the force keeping the object on the plane.
  • Another participant suggests that if the incline is flat and static friction is considered, the maximum angle can be derived from equating the forces acting on the object, leading to the relationship \(\tan(\alpha) = \mu\).
  • A third participant raises a distinction between sliding and toppling, indicating that for toppling, the critical factor is whether the vertical line through the center of mass extends beyond the base of the object.
  • The original poster clarifies that they are specifically interested in the angle at which the mass will no longer be in contact with the plane as it approaches 90 degrees.

Areas of Agreement / Disagreement

Participants express differing views on whether the focus should be on sliding or toppling, indicating that multiple competing perspectives remain unresolved.

Contextual Notes

There are assumptions regarding the conditions of sliding and toppling, as well as the definitions of forces involved, which may not be fully articulated or agreed upon.

Sinnaro
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I've been thinking about this for a model I'm devising. Assuming that you have an object of mass m, height h, coefficient of friction u, how large can you make the angle between the ground and the inclined plane. Otherwise, at what angle does the torque from the center of mass of the object overcome the force that is keeping the object on the inclined plane?
 
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If the incline is completely flat and the coefficient of friction is for static friction, then you can find the largest angle for which the mass won't slide by noting that the maximum force along the slide is usually modeled simply as the normal force times the coefficient, and you can equate that with the force from gravity down the incline, that is,

[tex]\mu F_n = \mu mg \cos(\alpha) = F_g = mg \sin(\alpha) \ \Rightarrow \ \tan(\alpha) = \mu[/tex]

where [itex]\alpha[/itex] is the angle and [itex]\mu[/itex] the coefficient of static friction.
 
Welcome to PF!

Hi Sinnaro! Welcome to PF! :wink:

I'm not sure whether you're talking about sliding (which as Filip Larsen :smile: says depends on whether the tangent exceeds the coefficient of static friction), or toppling.

If it's toppling, then all that matters is whether a vertical line through the centre of mass goes outside the base. :wink:
 
To clarify: it is assumed that the mass is sliding down the plane. I'm looking for the angle (as the angle approaches 90 degrees) for which the mass will no longer be in contact with the plane (falls off).

Picture of what I'm talking about. Assume that the mass looks similar to my drawing (tall vertical height with wide base):

http://i.imgur.com/kIwSt.png
 

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