Maximum energy stored in a capacitor? RLC circuit

In summary, the conversation discusses a series RLC circuit with a generator voltage that leads the current by 30 degrees. The circuit has an inductor of 400 mH, a resistor of 50 Ω, and an unknown capacitance. The first question is to find the capacitance, which is 145e-6F. The second question involves finding the energy stored in the capacitor at a specific time, which is given by UC = UC,max sin^2φ. The conversation then delves into the time dependence of the current and voltages, and the need for a phasor diagram.
  • #1
Luke Cohen
30
1

Homework Statement


The current in a series RLC circuit leads the generator voltage by φ = 30°. The circuit, containing an inductor L = 400 mH and a resistor R = 50 Ω, is driven by a generator operating at ω = 100 rad/s with a maximum emf of 10 V. The capacitance is unknown.

The first question regarding this prompt is to find the capacitance, which is 145e-6F.

This is the question I am stumped on:

In terms of the maximum energy UC,max stored in the capacitor and the angle φ by which the current leads the generator voltage, the energy UC stored in the capacitor when the time is t = π/2ω is:

The correct answer is UC = UC,max sin^2φ

Homework Equations

The Attempt at a Solution


I've drawn my phasor diagrams, but I don't understand the correct answer. Is the voltage across the capacitor the component of the voltage across the generator pointing in the direction of X_c, the capacitor's impedance? If so, I get how a sin^2(phi) term would be used, because that would be the V^2 part of U = 1/2*cV^2, but I don't see how that would give me UC,max *sin^2(phi).
I will appreciate any help!
 
Physics news on Phys.org
  • #2
This is just a normal box series RLC circuit with a battery, resistor, capacitor, and inductor in series. Sorry for not including!
 
  • #3
Y
Luke Cohen said:

Homework Statement


The current in a series RLC circuit leads the generator voltage by φ = 30°. The circuit, containing an inductor L = 400 mH and a resistor R = 50 Ω, is driven by a generator operating at ω = 100 rad/s with a maximum emf of 10 V. The capacitance is unknown.

The first question regarding this prompt is to find the capacitance, which is 145e-6F.

This is the question I am stumped on:

In terms of the maximum energy UC,max stored in the capacitor and the angle φ by which the current leads the generator voltage, the energy UC stored in the capacitor when the time is t = π/2ω is:

The correct answer is UC = UC,max sin^2φ

Homework Equations

The Attempt at a Solution


I've drawn my phasor diagrams, but I don't understand the correct answer. Is the voltage across the capacitor the component of the voltage across the generator pointing in the direction of X_c, the capacitor's impedance? If so, I get how a sin^2(phi) term would be used, because that would be the V^2 part of U = 1/2*cV^2, but I don't see how that would give me UC,max *sin^2(phi).
I will appreciate any help!
You have to work with time dependence of the current and voltages. Assuming the generator voltage is Vg=Vg0sin(ωt),
what is the time dependence of the current and the capacitor voltage?
 
  • #4
Luke Cohen said:
This is just a normal box series RLC circuit with a battery, resistor, capacitor, and inductor in series. Sorry for not including!

There is no escaping this: you will need to show, and then use, the phasor diagram of current and voltages.
 

Similar threads

Back
Top