- #1

naima

Gold Member

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I found this http://people.sissa.it/~benassi/capitolo1/node2.html [Broken]

in the vacuum the equations would be

q B = q E = 0

##q \times E = (\omega / c) B##

##q \times B = -(\omega / c) E##

Is there a typo? there is no t derivative.

If E = 0 B would have to be null.

Has B to be allways orthogonal to E (elliptic polarisation?)

thanks.

in the vacuum the equations would be

q B = q E = 0

##q \times E = (\omega / c) B##

##q \times B = -(\omega / c) E##

Is there a typo? there is no t derivative.

If E = 0 B would have to be null.

Has B to be allways orthogonal to E (elliptic polarisation?)

thanks.

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