Maxwell's velocity distribution

[Ben Hom Chen]

I have some problem in the paragragh.
I save it as Word format.The link is below.
Thanks!

http://www.badongo.com/file/3337594"

 

[Mentz114]

I downloaded the file, which is a zip containing some xml docs I will not open. You won't get any help unless you show your problem and your work.

 

[Ben Hom Chen]

http://www.badongo.com/file/3383953

I upload my problem again.

And I found that when downloading it,badongo system set the default
file format as "zipped file",so some error would happen.

When saving file,we must change the saving format to"All files",then it can
be opened without error.

I hope my words can be understood><

Thx><

 

[Mentz114]

Sorry, Ben, nothing has changed. I can't read the docx format. Try saving your document as PDF or .doc.

 

[Ben Hom Chen]

Ok,I save it as image now.

http://www.flickr.com/photos/8900006@N08/541975737/
http://www.flickr.com/photos/8900006@N08/541975749/

First it comes a paragraph from my textbook,then following my question.

Thank your reply and telling me there was some error.

 

[Mentz114]

OK, I can see the pictures. THis is the standard undergraduate derivation of the MB distribution.

1. $$\vec{v}^2 = v_x^2 + v_y^2 + v_z^2$$

2. Hmm. Maybe this should be "$$f(\vec{v}^2)$$ is the probabilty of finding a particle with squared velocity $$\vec{v}^2$$".

3. The function $$e^{ax}$$ is not normalizable unless a < 0. By convention one gives 'a' a positive value and writes the equation with a negative sign.

 

[Ben Hom Chen]

Thx for your help.
At least I understand the third answer^^"

 

[Mentz114]

I never liked that derivation, which I have in the Pauli lectures in it's full clunkiness. In fact it's possible to derive the MB distribution using a much simpler heuristic argument and I'll be happy to dig it out and post it if you like.

 

[Ben Hom Chen]

Thank You,I want to check it out.

If it won't take you much time.

 

[Mentz114]

Well, I found it but it's not simpler and relies on the central-limit theorem so maybe the standard derivation is the best after all.