Measurement (didn't understand solution)

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SUMMARY

The discussion centers on the misunderstanding of how an AC voltmeter measures a DC signal. The voltmeter, when connected to a 24V DC supply, reports an average voltage of 24V. However, since it is designed for AC measurements, it incorrectly applies a multiplication factor of 1.11, which is used for sine waves, leading to confusion about the RMS value. The key takeaway is that the AC voltmeter misinterprets the DC signal, resulting in an inaccurate representation of the voltage.

PREREQUISITES
  • Understanding of AC and DC voltage concepts
  • Knowledge of RMS (Root Mean Square) and average voltage calculations
  • Familiarity with voltmeter operation and measurement techniques
  • Basic principles of sine wave characteristics and their impact on measurements
NEXT STEPS
  • Research the differences between AC and DC voltmeter operation
  • Learn about RMS calculations for different waveforms
  • Explore the implications of using AC measurement tools on DC signals
  • Study the characteristics of sine waves and their effect on electrical measurements
USEFUL FOR

Electrical engineering students, technicians working with measurement tools, and anyone involved in voltage measurement and analysis will benefit from this discussion.

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Homework Statement


upload_2018-1-23_9-21-32.png


Homework Equations


For sine wave RMS/Avg = 1.11
For DC, RMS = Avg = Peak Value

The Attempt at a Solution


I didn't understand the solution. There is a 24V DC supply. I give it to an AV Voltmeter. The Voltmeter responds to average value. So the voltmeter would give 24V DC. So Answer should be A. I know that RMS / Avg = 1.11 for sine wave. But I didn't understand what they've said in solution.

Can somebody help me out?
 

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The voltmeter measures the average voltage, and since it is an AC voltmeter, it reports the RMS by multiplying the average by 1.11. Since it is sampling a DC signal, it gets an average of 24 V, but still assumes it is AC and applies the same multiplication factor.
 
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