Measuring pressure using a manometer.

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SUMMARY

The pressure of a gas cell was measured using a mercury manometer, revealing a height difference of 32.6 cm between the two arms. The calculation for gas pressure utilized the equation p(gas) = p(atmosphere) + ρ(gas density) * g(gravitational acceleration) * h(height difference), resulting in a pressure of 144.75 kPa. The discrepancy with the expected answer of 149.5 kPa was due to a misreading of the height as 36.2 cm instead of 32.6 cm. This discussion highlights the importance of careful reading in problem-solving.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with manometer operation and measurement
  • Knowledge of pressure equations and units
  • Basic skills in algebra for solving equations
NEXT STEPS
  • Study the principles of hydrostatic pressure in fluids
  • Learn about different types of manometers and their applications
  • Explore common errors in measurement and calculation in physics
  • Review atmospheric pressure variations and their effects on measurements
USEFUL FOR

Students in physics, engineers working with fluid systems, and anyone involved in pressure measurement and analysis will benefit from this discussion.

baddin
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Problem:
1. The pressure of a gas cell is measured with a mercurcy manometer. The mercury is 32.6 cm higher in the outside arm than in the arm connected to the gas cell. Calculate the gas pressure.


Relevant equations/given data
2. p(Pressure at depth h) = p(Pressure of atmosphere) + ρ(Density of liquid)*g(Gravitionational acceleration)*h
Pressure of atmosphere = 1atm = 101,300Pa. Density of mercury = 13,600kg/m^3


Attempted solution
3. p(gas) = p(Pressure of atmosphere) + ρ(Density of liquid)*g(Gravitionational acceleration)*h
p(gas) = 101,300 + (13600*9.8*0.326) = 144749.28Pa = 144.75kPa. I have the solution and it says the answer should be 149.5kPa. Have I done something wrong, or is the solution incorrect?
 
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Your calculation is exactly correct. The answer is the book is for a mercury height of 36.2cm. Is there any chance that you misread the problem and got the 6 and 2 backwards? If not, don't spend any more time thinking about it, you know what you are doing and the answer key had a typo.

Dr Peter Vaughan
BASIS Peoria Physics
 
Oh my! Stupid me! You are right, I misread the 6 and the 2 backwards. That clears it up, thanks for the help! =D
 
Those are absolutely the most difficult mistakes to find. Fortunately, they are also by far the least important mistakes.
 

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