Measuring torque acting on motor shaft?

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SUMMARY

This discussion focuses on measuring the average torque exerted by a DC motor driving an auger for pet food dispensing. Key equations include Powerin = Voltage * Current and Powerout = Torque * RPM, with efficiency defined as Powerout = Efficiency * Powerin. The motor's efficiency typically ranges from 60% to 75%, and while direct torque measurement is complex, it can be achieved using a torque sensor or by analyzing speed versus voltage curves. Understanding these parameters is crucial for optimizing motor performance.

PREREQUISITES
  • Understanding of DC motor operation and characteristics
  • Familiarity with electrical power equations (Powerin and Powerout)
  • Knowledge of torque measurement techniques
  • Basic principles of motor efficiency and performance metrics
NEXT STEPS
  • Research torque measurement methods using sensors, specifically torque sensors from Transducer Techniques
  • Explore the relationship between voltage, current, and efficiency in DC motors
  • Study speed versus voltage curves to deduce torque constants
  • Investigate motor efficiency optimization techniques for DC motors
USEFUL FOR

Engineers, hobbyists, and technicians involved in motor control, robotics, and automation who require precise torque measurements and efficiency analysis for DC motors.

robertjordan
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I have an electric motor that I am using to turn an auger to dispense pet food. I want to measure the average torque required to turn this auger at a given rpm.

I know Powerin = Voltage into motor * Current into motor
and Powerout = Torque exerted by shaft * RPM of auger
and Powerout = Efficiency of motor * Powerin

But how can I find the efficiency of the motor at different voltage inputs? I don't know anything about this motor (I don't even know if it's an AC or DC motor) beyond that it works when connected to a battery and that it changes directions when I swap the leads. How can I find average torque exerted on the shaft by the pet food? I can measure RPM, VoltageIn, and CurrentIn...
 
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I wouldn't worry about efficiency yet because it varies depending on the motor's operating point. The torque constant can be deduced from speed versus voltage curves. Speed and voltage are easy to measure. From what I've seen, measuring torque directly of a small DC motor requires comparatively elaborate and sensitive instrumentation.

Anyway, let's assume, for example, you want your motor to operate at maximum efficiency. In that case you then want the torque absorbed by the auger to equal the torque produced by the motor at the motor's maximum efficiency speed.

Technical correction: In the power out formula, torque is a physical quantity, whereas RPM is a unit of measure. I think you'd like all the variables to be physical quantities in this type of equation.
 

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