Mechanical energy of a wooden block sliding down an incline.

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Homework Help Overview

The discussion revolves around a wooden block sliding down an incline at an angle of 18.5 degrees, where kinetic friction is present. The original poster has conducted experiments measuring the time taken for the block to pass a photo-gate at various distances, aiming to calculate kinetic energy, potential energy, and changes in mechanical energy.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster calculated kinetic and potential energy and noted a negative slope in the graph of total mechanical energy versus displacement, attributing it to energy loss from friction. Some participants question the consistency of the measured velocities and the precision of the timing data.

Discussion Status

Participants are exploring the implications of the experimental results, particularly regarding the observed decrease in velocity with increased distance. There is recognition of potential experimental errors, and the original poster acknowledges the need to address these in their lab report.

Contextual Notes

Participants discuss the impact of equipment variability on results, as well as environmental factors that may have influenced the experiment, such as temperature and humidity. The original poster indicates they cannot repeat the experiment at this time.

Kot
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Homework Statement


A wooden block is on an incline with θ = 18.5 degrees. The angle was determined to be big enough that the wooden block would experience kinetic friction ( slides down the ramp). A photo-gate was used to measure the time it took for the block to move a certain distance. Five different trials are performed each time moving the block an increment of 10 centimeters away from the photo-gate. The distance of the block from the photo-gate are 0.2m, 0.3m, 0.4m, 0.5m, and 0.6m. The time it takes the block to pass the photo-gate is 0.31s, 0.31s, 0.313s, 0.36s, and 0.32s respectively. The velocities of each trial are about 0.18m/s for each trial. These values were calculated when I did my lab. I am supposed to calculate the kinetic energy, potential energy due to gravity, total change in mechanical energy and graph them in terms of the displacement.


Homework Equations


K=1/2mv2
U=mgh

The Attempt at a Solution


I was able to calculate the kinetic energy, potential energy and total change in mechanical energy of the wooden block. When I graphed displacement over change in total mechanical energy the graph was a line and had a negative slope. I assume that it is negative because the wooden block is losing energy due to friction while it travels down the incline so this results in a graph with a negative slope, is this correct?
 
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Kot said:
it is negative because the wooden block is losing energy due to friction while it travels down the incline so this results in a graph with a negative slope, is this correct?
Yes, but I'm surprised you always saw much the same speed. In fact, it seems to get slower as the run-up increases. Why is one time to 3 places of decimals and the others only to 2?
Seems to me your timings aren't precise enough to conclude much.
 
I rounded the times down and accidentally left that part in. Looking back on the graph I do find the velocities decreasing slowly. I think this was due to the equipment because on some trials we would get a significantly faster velocity than the previous trials at the same distance.
 
Kot said:
I rounded the times down and accidentally left that part in. Looking back on the graph I do find the velocities decreasing slowly. I think this was due to the equipment because on some trials we would get a significantly faster velocity than the previous trials at the same distance.
Something might have been changing... getting warmer, or damper etc. Maybe you should have repeated the set of distances a few times to see if there were any trend against passing time.
 
I will keep that in mind next time. I am unable to perform this experiment again at this time. I guess I have to state the error in my lab report.
 

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