Mechanical principles assistance.

Click For Summary
SUMMARY

This discussion focuses on calculating direct and shear stresses on bolts with an 18mm diameter, installed at a 60-degree angle to an applied load of 100 kN. The user seeks assistance in integrating the angle into their stress calculations, specifically using trigonometry to resolve the forces. Key advice includes breaking the applied load into components and ensuring accurate area calculations for the bolts. The discussion also emphasizes the importance of using correct unit symbols and notation in engineering calculations.

PREREQUISITES
  • Understanding of direct and shear stress calculations
  • Knowledge of trigonometry for resolving forces
  • Familiarity with engineering unit symbols and notation
  • Basic principles of mechanical engineering and bolt mechanics
NEXT STEPS
  • Study the method for resolving forces using trigonometry in mechanical applications
  • Learn about calculating the area of circles for stress analysis
  • Research the principles of safety factors in mechanical design
  • Explore the use of engineering notation and unit symbols in technical writing
USEFUL FOR

Engineering students, mechanical engineers, and anyone involved in stress analysis and mechanical design will benefit from this discussion.

studenteng
Messages
2
Reaction score
0

Homework Statement



Hello this is my first post.
Im currently studying towards a level three national diploma in engineering operations.
I need some assistance with a mechanical principles problem. ( A crude drawing of the problem has been attached haha)
I need to work out the direct and shear stresses on a pair of bolts with an 18mm diameter. The bolts are installed at a 60 degree angle to the applied load and share the loading equally the pull on the joint they are connected to is 100kn ( both sides). The part of the problem i am struggling with is intergrating the angle into my equations. I can work out shear and direct stresses easily when dealing on flat non angled surfaces, but I am struggling a bit with the angle.
Id appreciate a description of the method needed to work out the direct and shear stresses when dealing with an angle, rather than the actual answer as i won't learn anything. I am thinking ill need to use trigonometry to resolve this problem, as I am stumped in seeing any other way. Maybe some resoloution of forces? Any help will be greatley appreciated.

Homework Equations

-

The Attempt at a Solution


I also need to work out the limiting factor of safety for both bolts, which i can do without any assistance.
I work direct stress to be f/a = 110kn /(pi (18x10 to the -3 ) / 4) = Direct stress per bolt. But once again I am not sure if this is even right as i haven't taken the angle into consideration.
Basically i need some form of assistance.
 

Attachments

  • Untitled.jpg
    Untitled.jpg
    5.1 KB · Views: 478
Physics news on Phys.org
studenteng: Yes, go ahead and break the applied load into components, using trigonometry. You must list relevant equations yourself, and show your work. And then someone might check your math.

Check your calculation of area of a circle; your area calculation currently looks incorrect. And, the total applied load should not be applied as tensile force.

(1) By the way, always leave a space between a numeric value and its following unit symbol. E.g., 18 mm, not 18mm.

(2) The unit symbol for kiloNewton is spelled kN, not kn. Lowercase n means nano. Always use correct capitalization of units.

(3) For exponentiation, use the caret (^) symbol. E.g., 10^-3, not "10 to the -3."

(4) For scientific notation, you can use 18e-3.
 
Thanks for the reply.
Thanks for the tips, i am aware of the lack of accuracy in my post i was in a rush, i will take care to formulate my calculations properley next time
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
7
Views
7K
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
11K
  • · Replies 9 ·
Replies
9
Views
4K