Mechanics of Materials: stress due to thermal expansion

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Discussion Overview

The discussion revolves around a homework problem involving the mechanics of materials, specifically focusing on the stress due to thermal expansion in a magnesium alloy tube capped with a rigid plate and a solid aluminum rod. Participants explore the conditions under which the normal stress at the interface between the tube and the rod is zero, particularly in relation to temperature changes.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states the problem involves finding the maximum temperature increase from an initial temperature T_1 such that the normal stress at the interface is zero.
  • Another participant clarifies that the problem is asking for the maximum temperature increase where there is no contact force between the tube and rod, indicating that there will be no stress at this point.
  • A participant proposes a method to calculate the temperature increase by setting the total elongation of the tube and rod equal to the gap distance d, leading to a derived formula for the final temperature T_2.
  • There is an acknowledgment of the elongation of the shafts with temperature increase and the need to find the specific temperature at which their combined length increase equals the gap distance.

Areas of Agreement / Disagreement

Participants generally agree on the approach to solving the problem, particularly regarding the relationship between temperature increase and elongation of the materials. However, the discussion does not resolve all uncertainties, particularly regarding the assumptions made in the calculations.

Contextual Notes

Participants express uncertainty about the initial conditions and the specific parameters involved, such as the coefficients of thermal expansion for the materials. There is also a mention of issues with formatting equations, which may affect clarity.

steak313
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Homework Statement



The magnesium allow tube (AM1004-T61) AB is capped with a rigid plate. The gap between E and end C of 6061-T6 alluminum alloy solid circular rod CD is d[m] when the temperature is T_1 degrees celsius.

[PLAIN]http://img27.imageshack.us/img27/8867/problemwn.jpg

The left tube is fixed on the left end. The right shaft is fixed on the right side.

Find the maximum temperature increase from T_1 such that the normal stress at the interface between the tube and the rod is 0.


Homework Equations



Well for some reason no matter what I change the latex text to, something completely unrelated shows up in its place. Not sure how to fix this but I want it to say:
(change in length)= (alpha)(change in temperature)(Length).

sigma=(pressure)/(cross sectional area)

The Attempt at a Solution



Hopefully the image shows up in a timely manner. It is a pretty crude sketch so if any clarification is needed that is fine. Let me also state that I am essentially trying to learn the material as I do this so bare with me.

My First thoughts were that the tubes would elongate as the temperature increases. As the they enlongate, the distance between the two will get smaller and smaller until they are pressing against one another. My assumption is that I need to show the temperature increase such that the force from the two shafts are equal but opposite at the interface.

Before I begin to tackle the problem, would anyone be interested in commenting on my approach or my assumptions? Is this in fact what the problem is asking of me?
 
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The problem is asking for the max temp increase such that there is no contact force between the tube and rod (N=0). There is obviously no contact force at T1 with that gap. And there still won't be any with a temp increase when they are just on the verge of touching. There won't be any stress, either.
 
Thank you very much for your response!

Okay so essentially increasing the temperature will elongate the shafts. I need to find the temperature when the combined length increase is d[m].

For AB \delta_1 = \alpha_1 (T_2 - T_1)L_AB

For CD \delta_2 = \alpha_2 (T_2 - T_1)L_CD

I set the sum of these two equations equal length d[m] then solved for T_2

d = \alpha_1 (T_2 - T_1)L_AB + \alpha_2 (T_2 - T_1)L_CD

after some manipulation

T_2 = \frac{d}{\alpha_1 L_ab + \alpha_2 L_CD} + T_1
 
Last edited:

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