Defining Membership Uniqueness in a Set X with One True Value

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The discussion focuses on defining the uniqueness of a member within a set X, specifically identifying a single element whose evaluation with a function f() yields true. The original notation presented was deemed insufficient, prompting suggestions for more precise mathematical expressions, including the use of count functions and quantifiers to indicate uniqueness. It was highlighted that understanding "uniqueness" can vary based on context, such as distinguishing between knowing there is one unique member versus identifying which one it is. A practical solution involved creating a family of sets with unique properties to ensure that intersections contained exactly one member. The conversation emphasizes the need for clear mathematical notation to convey the concept of uniqueness effectively.
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Hello All,

I am trying to define a uniqueness of a member of a set, please bear with me as my notation is not as refined as it ought to be:

For a set X:

{ x(i) } union { f(x(j)) = true, where j is not equal to i } = { x(i) }

what I am trying to say is, for this set X there exists only one member whose evaluation with f() results in true.

I am defining this by saying that the union of any element with any other element other than itself in the set who's value is true is equal to the first element, however this doesn't quite work - I almost need a count() function on the right side and say that the count() is always = 1.

Is there a more correct elegant way to say this?
 
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Yes, you can use the "count" function. The common mathematical notation for this is |{...}| or #{...}:

\left| \{ x \in X \mid f(x) = \text{true} \} \right| = 1
\#\{ x \in X \mid f(x) = \text{true} \} = 1

Or you could use quantifiers:
\exists! x \in X: f(x) = \text{true}
(I don't know if this is official notation, with the ! meaning "unique", but I'm pretty sure any mathematician will understand it).

Or you could write this correct-but-ugly line,
\exists x \in X: \left( f(x) = \text{true} \wedge \forall y \in X: y \neq x \implies f(x) \neq \text{true} \right)
 
delphi said:
Hello All,

I'm trying to define a uniqueness of a member of a set, please bear with me as my notation is not as refined as it ought to be:

what I am trying to say is, for this set X there exists only one member whose evaluation with f() results in true.

It depends on what you mean by "uniqueness". Ir's one thing to know there's exactly one murderer in the room, and another to know which person in the room is the murderer. If you want to know who the murderer is, there needs to be some identifying property or set of properties.

This was a practical problem for me in my work. We solved the problem by creating a family of sets Ai such that each set was identified with a unique property in a way that an intersection of some of the sets contained exactly one member.
 
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I was reading documentation about the soundness and completeness of logic formal systems. Consider the following $$\vdash_S \phi$$ where ##S## is the proof-system making part the formal system and ##\phi## is a wff (well formed formula) of the formal language. Note the blank on left of the turnstile symbol ##\vdash_S##, as far as I can tell it actually represents the empty set. So what does it mean ? I guess it actually means ##\phi## is a theorem of the formal system, i.e. there is a...

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