Min and Max of Parallel Resistors

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In a parallel resistor circuit, the minimum resistance occurs when R2 approaches R1, resulting in a value of R1/2, while the maximum resistance approaches R1 as R2 becomes infinitely large. The formula for total resistance in a parallel circuit is R1.R2/(R1 + R2). Empirical observations suggest that for multiple resistors, the minimum resistance is R1/n and the maximum remains R1. To explore these relationships further, one can analyze the behavior of resistance as R2 varies, particularly when it is just above R1 and when it approaches infinity. This exploration can provide deeper insights into the mathematical proof of these resistance limits.
meeep
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I noticed that, for resistors in a parallel circuit, where R1 is < R2, the minimum value is (R1)/2, and the maximum approaches R1.
I was trying to work out why, so for two resistors, the calculation is:
R1.R2/(R1 + R2).
I thought of partial derivatives but not sure where to go after that, and after getting the curve in WolframAlpha, not sure what to do with that either.
http://www.wolframalpha.com/input/?i=plot+xy/(x+y)

Empirically, the nth case appears to be: min = (R1)/n and max = R1, but not sure how to prove it mathematically.

Any advice on what I could try next? This isn't homework, just noticed it and got curious.
 
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Assume that R1 is some fixed number. All that we know is that R2 must be bigger than R1. So to find the minimum resistance, R2 should be as small as possible, and to find the maximum resistance, R2 should be infinitely large.

Try seeing what happens to the resistance when you make R2 as small as possible (keeping in mind it must be bigger than R1) and what happens when R2 is arbitrarily large
 
Good morning I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...

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