Hello, I'm in an applied calculus class and we just recieved a project that my group is having some small issues with. We have find the minimum cost of a tin can using calculus. From the text, " You must design a cylindrical tin can which is to hold 100 cubic inches of material. The tin for the side of the can is to cost A cents per square inch and the tin for the ens is to cost b cents per square inch. The seams for the top and bottom of the can will cost C cents while the seam up the side will cost d cents per inch. find the heigh tand radius of the tin can that will cost the least to make. After you have computed the dimensions for the can with your information you must make an accurate drawing of the can in proper dimensions. The drawing may be done to some scale if neccessary." This is what we have so far. Cost should equal A(LxW)+B(2xPixr^2)+C(4xPixr)+D(H) L = Length W = Width r = Radius H = Height We came up with this because we drew the can flat with a rectangle attached to two circles. The rectangle being the sides of the can and the circles being the top and bottom. Cost Evaluations (cents) A= .31 B= .21 C= .08 D=.04 We know we can figure this out easily without using calculus but we just dont know where to use calculus... such as where to find the derivatives ect ect. The professor gave us the start of an equation that we dont understand how to use which was... C(h,r)=A(2xpixrxH)+... each part C(r) C'(r)=0 Any help with this would be greatly appreciated.