Minimising the perimeter of a tunnel with a fixed area

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To minimize the perimeter of a tunnel with a fixed cross-sectional area, the shape consists of a rectangle topped by a semicircle. The perimeter is expressed as P = πr + 4r + 2h, while the area is given by A = 0.5πr^2 + 2rh. By using the area equation, a relationship between the radius (r) and height (h) can be established, allowing the problem to be simplified to one variable. The next step involves applying differential calculus to find the value that minimizes the perimeter. This approach effectively combines geometry and calculus to achieve the desired outcome.
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Homework Statement


A tunnel cross-section is to have the shape of a rectangle surmounted by a semicircular roof. The total cross-sectional area must be A, but the perimeter minimised to save building costs. Find its dimensions


Homework Equations





The Attempt at a Solution


I have that the perimeter would equal pi*r + 4r + 2h (where r is the radius of semi circle, h is height of rectangle) and that A=0.5pi*r^2 + 2rh, but am unsure as to how to get started. Any help would be appreciated.
 
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The fact that area must be equal to 'A' has given you a second equation. From it, you can determine the required relationship between r and h...meaning that the problem is reduced down to one variable (either r or h). Finding the value of that one variable that minimizes the perimeter is then just a differential calculus problem.
 
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