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A() 61 kg child stands at the rim of a merrygo-round of radius 1.05 m, rotating with an

angular speed of 1.87 rad/s

The acceleration of gravity is 9.8 m/s^2

What is the child’s centripetal acceleration?

Answer in units of m/s

What minimum force between her feet and

the ﬂoor of the carousel is required to keep

her in the circular path?

Answer in units of N

What minimum coeﬃcient of static friction is

required?

1)

I found the centripetal acceleration since a = v^2/r and v = 1.9635 and r = 1.05.

The acceleration is 3.671745

2) I found the force which is F=ma

F = 61(3.671745) = 223.976445 N

3) I'm confused as to how I should solve for the minimum of coefficient of friction.

Help is appreciated!

angular speed of 1.87 rad/s

The acceleration of gravity is 9.8 m/s^2

What is the child’s centripetal acceleration?

Answer in units of m/s

What minimum force between her feet and

the ﬂoor of the carousel is required to keep

her in the circular path?

Answer in units of N

What minimum coeﬃcient of static friction is

required?

## The Attempt at a Solution

1)

I found the centripetal acceleration since a = v^2/r and v = 1.9635 and r = 1.05.

The acceleration is 3.671745

2) I found the force which is F=ma

F = 61(3.671745) = 223.976445 N

3) I'm confused as to how I should solve for the minimum of coefficient of friction.

Help is appreciated!