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A() 61 kg child stands at the rim of a merrygoround of radius 1.05 m, rotating with an
angular speed of 1.87 rad/s
The acceleration of gravity is 9.8 m/s^2
What is the child’s centripetal acceleration?
Answer in units of m/s
What minimum force between her feet and
the ﬂoor of the carousel is required to keep
her in the circular path?
Answer in units of N
What minimum coeﬃcient of static friction is
required?
1)
I found the centripetal acceleration since a = v^2/r and v = 1.9635 and r = 1.05.
The acceleration is 3.671745
2) I found the force which is F=ma
F = 61(3.671745) = 223.976445 N
3) I'm confused as to how I should solve for the minimum of coefficient of friction.
Help is appreciated!!
angular speed of 1.87 rad/s
The acceleration of gravity is 9.8 m/s^2
What is the child’s centripetal acceleration?
Answer in units of m/s
What minimum force between her feet and
the ﬂoor of the carousel is required to keep
her in the circular path?
Answer in units of N
What minimum coeﬃcient of static friction is
required?
The Attempt at a Solution
1)
I found the centripetal acceleration since a = v^2/r and v = 1.9635 and r = 1.05.
The acceleration is 3.671745
2) I found the force which is F=ma
F = 61(3.671745) = 223.976445 N
3) I'm confused as to how I should solve for the minimum of coefficient of friction.
Help is appreciated!!
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