# Minimum linear velocity attained by sphere

1. Nov 8, 2013

### utkarshakash

1. The problem statement, all variables and given/known data
A sphere of mass M and radius R is moving on a rough fixed surface, having co-efficient of friction μ, with a velocity v towards right and angular velocity ω clockwise. It will attain a minimum linear velocity at time (take v>ωR)

3. The attempt at a solution
Since v>ωR the sphere rolls with slipping. So frictional force will act in the backward direction. Using the equation $\int \tau dt = \int dL$ where τ=μmgR.

$\mu mgRt= \frac{2}{5} mR^2 (\omega ' - \omega) \\ \mu mg = m \frac{dv}{dt} \\ \mu gt = (v' - v)$

Using the relation v'=ω'R and solving the above two equations I get
t= 2(v-ωR)/3μg. But the correct answer has 7 in the denominator.

2. Nov 8, 2013

### Staff: Mentor

There is a minus sign missing.

I don't see why this point is called "minimum linear velocity" - it is the point where the sphere stops slipping.

3. Nov 8, 2013

### utkarshakash

Why there should be a minus sign? Since friction acts backwards, so is the acceleration. Hence both minus cancels out. Are you trying to say that since velocity is decreasing that's why dv/dt should carry a '-' with it?

4. Nov 8, 2013

### Staff: Mentor

Acceleration is backwards, but as you write your equation both sides are positive, so v increases. You can use a negative v everywhere, but then things get really confusing and the initial v>ωR does not work.